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Answer:
#3 a. g(-1) = 2, g(0) = 3, and g(1) = 2
b. No restrictions for all real numbers
b. Yes, <em>x ≠ 2</em>
Step-by-step explanation:
#3 The function is given as g(x) = -x² + 3
a. From the given function, by plugging in the value of 'x' in the bracket, we have;
g(-1) = -(-1)² + 3 = -1 + 3 = 2
g(-1) = 2
g(0) = -0² + 3 = 3
g(0) = 3
g(1) = -1² + 3 = -1 + 3 = 2
g(1) = 2
g(-1) = 2, g(0) = 3, and g(1) = 2
b. The given function g(x) = -x² + 3 for finding the value of <em>g</em> can take any value of <em>x</em> which is a real number
Therefore, therefore, there are no restrictions
#4 a. The given function is given as follows;
By substitution, we get;
b. From the values of the function, we have that h(x) is not defined at x = 2
Therefore, there is a restriction for <em>x</em> in the function, which is <em>x ≠ 2</em>
Answer:
x = -1 ± √6 / 5
Step-by-step explanation:
Solve + 2x = 1
move 1 to the left side of the equation by subtracting it from both sides.
+ 2x - 1 = 0
Use the quadratic formula to find the solutions.
-b± / 2a
Substitute the values a = 5 , b = 2, and c = -1 into the quadratic formula and solve for x
-2±/ 2 ⋅ 5
Simplify.
x = -2 ± 2 / 10
x = -1 ± / 5
Exact Form:
x = -1 ± / 5