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3 years ago

How many astronauts have walked on the moon?

1 answer:

6 0

12 astronauts have walked on the moon. The people are Neil Armstrong, Edwin Aldrin, Charles Conrad, Alan Bean, Alan Shepard, Edgar Mitchell, David Randolph Scott, James Irwin, John Young, Charles Duke Jr., Harrison Schmitt, and Eugene Cernan. Hope this helps :)

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Each tire on a car has a radius of 0.330 m and is rotating with an angular speed of 13.9 revolutions/s. Find the linear speed v

Lostsunrise [7]

Answer:

the linear speed of the car is 28.83 m/s

Explanation:

Given;

radius of the car, r = 0.33 m

angular speed of each tire, ω = 13.9 rev/s = 13.9 x 2π = 87.35 rad/s

The linear speed of the car is calculated as;

V = ωr

V = 87.35 rad/s x 0.33 m

V = 28.83 m/s

Therefore, the linear speed of the car is 28.83 m/s

3 0

3 years ago

The current in a wire is 4.00A. How much time is needed for 1 mole of electrons (6.02×1023 electrons) to pass a point in the wir

scZoUnD [109]

Answer:

t= 24080 s

Explanation:

Given that

Current in the wire ,I = 4 A

The charge ,q = 6.02 x 10²³ e C

We know that

$I=\dfrac{q}{t}$

I=Current

q=Charge

t=time

$t=\dfrac{q}{I}$

Now by putting the values in the above equation we get'

$t=\dfrac{6.02\times 10^{23}\times 1.6\times 10^{-19}}{4}\ s$

t= 24080 s

8 0

3 years ago

If a rock has a speed of 12 m/s as it hits the ground, from what height did it

grin007 [14]

Answer:

To find the height the following formula should be used:

v 2 = u 2 + 2aH

Explanation:

Assuming this occurs on earth, a= 9.8 ms -2

-2 2

12=0+2 x9.8 x H

144

_______ =H

2 x 9.8

H= 7.35m

6 0

3 years ago

A small segment of wire contains 10 nC of charge. The segment is shrunk to one-third of its original length. A proton is very fa

Alik [6]

To solve this problem we will apply the concepts related to the electric field, linear charge density and electrostatic force.

The electric field is

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Here,

$\lambda$ = Linear charge density

$\epsilon_0$ = Permittivity of free space

r = Distance

The linear charge density can be written as,

Linear charge density is given as

$\lambda = \frac{q}{L}$

Replacing,

$E = \frac{\frac{q}{L}}{2\pi \epsilon_0 r}$

$E = \frac{q}{2\pi \epsilon_0 rL}$

The initial and final electric Force can be written as function of the charge and the electric field as

$F_i = E_i q$

$F_f = E_f q$

If we replace the value for the electric field we have,

$F_i = (\frac{q}{2\pi \epsilon_0 rL})q = (\frac{q^2}{2\pi \epsilon_0 rL})$

Length is one third at the end, then

$F_f = (\frac{q}{2\pi \epsilon_0 r(L/3)})q = (\frac{3q^2}{2\pi \epsilon_0 rL})$

The ratio of the force is

$\frac{F_f}{F_i} = \frac{(\frac{3q^2}{2\pi \epsilon_0 rL})}{(\frac{q^2}{2\pi \epsilon_0 rL})}$

$\frac{F_f}{F_i} = 3$

Therefore the required ratio is 3

7 0

3 years ago

Suppose your grocery cart is moving at a constant momentum in a straight line down the aisle of a store, without friction. How w

Strike441 [17]

Answer:

It will increase

Explanation:

The kinetic energy is the energy possessed by a moving object and is given by:

KE = $1/2 mv^2$

where m = mass of the object and v = velocity of the object.

It does means that the more the mass of an object in motion, the more the kinetic energy of the object if there are no opposing force such as friction. Also, the more the kinetic energy of the object, the more the speed of that object.

<em>Hence, as the weight of the cart increases by addition of groceries, the kinetic energy increases and the speed also increases as it moves along the frictionless surface.</em>

7 0

3 years ago