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dalvyx [7]
3 years ago
15

Solve the system x+3=22 2x-y=2

Mathematics
1 answer:
steposvetlana [31]3 years ago
3 0

Hello from MrBillDoesMath!

Answer:

x = 19, y = 36

Discussion:

x + 3 = 22     (*)

2x - y = 2      (**)


Subtract 3 from both sides of (*)

x + 3 -3 = 22 = 3 = 19  =>

x = 19


Substitute x= 19 in (**)

2(19) - y = 2 =>

38 - y = 2 =>           (add y to both sides)

38 -y + y = 2 + y =>

38 = 2 + y  =>         (subtract 2 from both sides)

38 -2 = 2 -2 + y =>

36 = y


Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


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Step-by-step explanation:

If one root is -7i, another root must be 7i.  You can't just have one root with i.  The other roos is √2, so there are 3 roots.  

x = -7i       is one root,

   (x + 7i) = 0    is the factor

x = 7i       is one root

  (x - 7i) = 0     is the factor

x = √2      is one root

    (x - √2) = 0   is the factor

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