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Natalija [7]
3 years ago
5

For the geometric sequence 3, 6, 12..., find the 13th term and state the common ratio of the sequence​

Mathematics
1 answer:
ddd [48]3 years ago
5 0

Common ratio, is r=6/3=12/6=2

Answer: common ratio 2

First term a₁ = 3

nth term  aₙ = a₁rⁿ⁻¹ = 3 (2ⁿ⁻¹)

13th term = 3(2¹²) = 12288

Answer: 13th term is 12,288

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N/4 less than or equal to 5
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The circumference of a circle is 5 Pi cm. What is the area of the circle?
Ber [7]

Answer:

6.25 pi cm^2

Step-by-step explanation:

The formula for circumference is

C = 2*pi*r

We know the circumference is 5 pi

5 pi = 2 * pi *r

Divide each side by pi

5 pi/pi = 2 * pi *r/pi

5 = 2r

Divide by 2

5/2 = 2r/2

2.5 = r

We need to find the area of the circle

The area is given by

A = pi * r^2

   = pi * (2/5)^2

    = pi *6.25

    = 6.25 pi cm^2

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3 years ago
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HELP, Prove: (cos(x))/(sin(x)tan(x))=cot^2x
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Answer:

Steps shown below

Step-by-step explanation:

We will simplify this using definitions and identities. Let's start.

\frac{cos(x)}{sin(x)tan(x)}

Using tanx=\frac{sinx}{cosx}, we have:

\frac{cos(x)}{sin(x)\frac{sin(x)}{cos(x)}}\\=\frac{cos^2(x)}{sin^2(x)}

Using cot(x)=\frac{cos(x)}{sin(x)}, we have:

\frac{cos^2(x)}{sin^2(x)}\\=cot^2(x)

Hence, proved.

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Which one of the following examples represents a proper fraction? 
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The answer is D. 15/22
4 0
3 years ago
Seattle-Pipes Co. produces pipes to be supplied to a Seattle utility company. The requirement of the utility company is that the
g100num [7]

Answer:

Step-by-step explanation:

Hello!

The study variable is

X: Pipe length.

It is known that this variable has a normal distribution and that the distribution parameter varies depending on the process used to manufacture the pipes.

Process A: μ= 200cm δ= 0.5cm

Process B: μ=201cm δ= 1cm

Process C: μ=202cm δ= 1.5cm

Pipes with a length of 200cm or more will be accepted by the utility company (X≥200), but pipes with less than 200cm length will be rejected (X<200)

a. Using Process C, you need to calculate the probability that the pipe will be rejected, symbolically:

P(X<200)

Using the distribution data of process C you have to standardize the value:

P(Z<(200-202)/1.5)= P(Z<-1.33)= 0.09176

b. The requirements change, accepting any pipe between 199 and 202, you have to calculate the probabilities of the pipes being between those lengths using the three process:

Process A:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-200)/0.5)) - P(Z≤(199-200)/0.5))

P(Z≤4) - P(Z≤-2) = 1 - 0.02275 = 0.97725

The probability of the pipe being rejected is 0.02275

Process B:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-201)/1)) - P(Z≤(199-201)/1))

P(Z≤1) - P(Z≤-2) = 0.84134 - 0.02275 = 0.81859

The probability of the pipe being rejected is 1-0.81859= 0.18141

Process C:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-202)/1.5)) - P(Z≤(199-202)/1.5))

P(Z≤0) - P(Z≤-2) = 0.5 - 0.02275 = 0.47725

The probability of the pipe being rejected is 1-0.47725= 0.52275

The pipes manufactured using process A has fewer chances of being rejected.

c.

Process A costs $140

P(X≥200)= 1 - P(X<200)= 1 - P(Z<0)= 1 - 0.5= 0.5

Process B costs $160

P(X≥200)= 1 - P(X<200)= 1 - P(Z<-1)= 1 - 0.15866= 0.84134

Process C costs $177

P(X≥200)= 1 - P(X<200)= 1 - P(Z<-1.33)= 1 - 0.09176= 0.90824

If they where to make 100 pipes:

Using process A: 100*0.5= 50 pipes will be accepted, so they'll win 50*($200-$140)= $3000

Using process B: 100*0.84134= 84.134≅ 84 pipes will beaccepted, so they'll win 84*($200-$160)= $3360

Using the process C: 100*0.90824= 80.824≅ 90 pipes will be accepted, so they'll win 90*($200-$177)= $2070

As you can see, using process B will maximize the profits.

I hope it helps!

4 0
3 years ago
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