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Blizzard [7]
3 years ago
7

Really need help

Mathematics
1 answer:
Ket [755]3 years ago
4 0
3n - 80 = 5n + 8\\3n=5n + 88\\ -2n = 88\\\\ n = -44
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Is it a function????
Troyanec [42]
Yes... according to what I know:)Let
me know if I’m wrong
7 0
3 years ago
Which of the following data could be graphed using a dot plot? Select all that apply.
Sphinxa [80]

Answer:

Time taken to complete a test.

-Number of cars in a -household.

-Number of siblings

Distance driven to school.

Step-by-step explanation:

Data used for a dot plot is relatively small data set where the values can fall into a number of categories/bins. Dot plots are used for univariate data where the variable is quantitative or categorical

5 0
3 years ago
5 times what equals 200
KATRIN_1 [288]
200 divided by 5 equals 40.
So therefore, 40 times 5 equals 200.
8 0
3 years ago
Read 2 more answers
Kelly has a rectangular fish aquarium that measures 18 inches long, 8 inches wide, and 12 inches tall.
BigorU [14]

Answer:

a) The maximum amount of water the aquarium can hold is 1728 in³.

b) The cover has to be 624 in² big.

Step-by-step explanation:

a) The maximum volume of water that the aquarium can have is the same as the volume of the aquarium:

V=L×W×H=18 in × 8 in × 12 in= 1728 in³

b) The protective covering is used on the four walls of the aquarium. We have to find the areas of the four walls:

One of them is given by the multiplication of the width and the height:

A₁= W×H= 8 in × 12 in=96 in²

The other area is given by the multiplication of the length and the height:

A₂= L×H= 18 in × 12 in= 216 in²

As the fish aquarium is rectangular the area of the walls is given by:

A_T=2A_1+2A_2=2×96 in²+2×216 in²=624 in²

8 0
3 years ago
A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte
ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, q_1 = Q- r \times Q

q_1 = Q(1-r)\cdots(i)

The value of quantity after 2 months, q_2 = q_1- r \times q_1

q_2 = q_1(1-r)

From equation (i)

q_2=Q(1-r)(1-r)  \\\\q_2=Q(1-r)^2\cdots(ii)

The value of quantity after 3 months, q_3 = q_2- r \times q_2

q_3 = q_2(1-r)

From equation (ii)

q_3=Q(1-r)^2(1-r)

q_3=Q(1-r)^3

Similarly, the value of quantity after n months,

q_n= Q(1- r)^n

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

q_{48}=Q(1-r)^{48}

Putting Q=6200 and r=5.5%=0.055, we have

q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32

Hence, the value of quantity after 4 years is 410.32.

4 0
3 years ago
Read 2 more answers
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