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nevsk [136]
3 years ago
8

Can anyone help with this?

Mathematics
2 answers:
Marrrta [24]3 years ago
6 0
3 x 2 and 1/3? The answer is 7.
Kruka [31]3 years ago
5 0
The answer is 7. You would make 3 as a fraction (3/1). Then you simplify 2 1/3 into 7/3. Now you just multiply across to get 7.
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Which of the is the same as2.3×10^3
dalvyx [7]
2300 you mover the decimal over 3 spaces
7 0
4 years ago
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The height of a triangle is 8cm more than the base. If the area is 90cm^2, find the base and the height
Aleonysh [2.5K]
I get the base to be 4.74 and the height to be 12.74
3 0
3 years ago
Help please urgent 25 point
uranmaximum [27]

Answer:

60

Step-by-step explanation:

b = the hypotenuse of a right angle triangle

a = the adjacent side.

R is being defined by the cosine

cos(R) = adjacent /  hypotenuse

adjacent = 16* sqrt(2)

hypotenuse = 32*sqrt(2)

Cos(R) = 16*sqrt(2) / 32*sqrt(2)      sqrt(2) cancels.

cos(R) = 1/2

R = cos-1(1/2)

R = 60 degrees.

4 0
3 years ago
Which statement is the most appropriate comparison of the spreads?
babunello [35]

Answer:

D  The IQR for town A is less than the IQR for town B

Step-by-step explanation:

A small IQR indicates that the points are closer together, while a larger IQR means that the points are scattered and that the plot is skewed in a certain direction. As you can see, town A's plot looks fairly balanced, while town B's plot is skewing to the left. Hope this helps :)

8 0
3 years ago
Hi, the answer is K but can anyone show why
dlinn [17]

Let's do 51 and 52.

51. The contrapositive has the same truth value as the original statement. That's opposed to the converse, which may or may not be true independent of the original statement.

The contrapositive of IF P THEN Q is IF not Q THEN not P.  They're equivalent.  Here that's If the cat is not female then it is not tricolor.

Answer: C

52.  

(x^3)^{(4-b^2)}=1

x^{3(4-b^2)} = 1

For the statement to be true, the exponent must be zero:

3(4-b^2) = 0

b^2 = 4

b = \pm 2

Both positive 2 and negative 2 have a square of 4.

Answer: K

By the way, usually we assume 0^0=1 so the restriction that x \ne 0 isn't really necessary.  Think of the definition of a polynomial or the binomial expansion:

\displaystyle f(x)=\sum_{k=0}^n a_k x^k

\displaystyle(x+y)^n=\sum_{k=0}^n {n \choose k} x^{k}y^{n-k}

For these common equalities to work when x=0 we need to define 0^0=1


3 0
4 years ago
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