3 years ago

How do I find arc mSQ

Mathematics

1 answer:

Norma-Jean [14]3 years ago

7 0

Check the picture below.

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What is the slope of the line?

Lapatulllka [165]

Answer:

$m=\frac{2}{3}$

Step-by-step explanation:

We can see that some of the points that are plotted we can tell what those plots are (-2, 0) (1, 2) (4, 4)

We use the slope formula $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ for any of the two plots that are shown on the line

8 0

2 years ago

Consider F and C below. F(x, y) = x4y5i + x5y4j, C: r(t) = t3 − 2t, t3 + 2t , 0 ≤ t ≤ 1 (a) Find a function f such that F = ∇f.

vovikov84 [41]

$\mathbf f(x,y)=x^4y^5\,\mathbf i+x^5y^4\,\mathbf j$

We want a scalar function $f(x,y)$ whose gradient is equivalent to the vector field. That means

$\dfrac{\partial f}{\partial x}=x^4y^5\implies f(x,y)=\dfrac{x^5y^5}5+g(y)$
$\dfrac{\partial f}{\partial y}=x^5y^4\implies x^5y^4=x^5y^4+\dfrac{\mathrm dg}{\mathrm dy}$
$\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C$

So (a)

$f(x,y)=\dfrac{x^5y^5}5+C$

which means (b)

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(\mathbf r(1))-f(\mathbf r(0))=f(-1,3)-f(0,0)=-\dfrac{243}5-0=-\dfrac{243}5$

5 0

2 years ago

Is this correct? if not please let me know how to solve it

Degger [83]

That is correct.
You have applied the distributive law.

6 0

3 years ago

Read 2 more answers

Which expression correctly represents "eight times the difference of four and a number"?

il63 [147K]

Answer:

8(4-x)