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Daniel [21]
3 years ago
9

about how much can someone with a professional degree expect to earn compared to someone with a high school diploma who didn't a

ttend college
Engineering
2 answers:
Tema [17]3 years ago
7 0

if you know what you are doing, are good at it and of course enjoy it, you can even be the best with only a high school diploma.

Elena L [17]3 years ago
6 0
Depending on the career, most people who don’t have a college degree now a days can only make up to 18 $ an hour. w/ a degree (depending on what career) you can make well over 30$ an hour
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To avoid carbon monoxide poisoning, use the heater or air conditioner in a parked car with the windows closed.T/F
liberstina [14]

Answer: false

Explanation:

because when you get in the car the cm will build up

3 0
2 years ago
Why Elastic Modulus is important and on what it depends?
Bad White [126]

Answer:

The Young's Modulus of a material is a fundamental property of every material that cannot be changed. It is dependent upon temperature and pressure however. The Young's Modulus (or Elastic Modulus) is in essence the stiffness of a material. In other words, it is how easily it is bended or stretched.

Explanation:

Have a great day

5 0
3 years ago
A European car manufacturer reports that the fuel efficiency of the new MicroCar is 48.5 km/L highway and 42.0 km/L city. What a
statuscvo [17]

Answer:

Fuel efficiency for highway = 114.08 miles/gallon

Fuel efficiency for city = 98.79 miles/gallon

Explanation:

1 gallon = 3.7854 litres

1 mile = 1.6093 km

Let's first convert the efficiency to km/gallon:

48.5 km/litre = (48.5 * 3.7854) km/gallon

48.5 km/litre =  183.5919 km/gallon (highway)

42.0 km/litre = (42.0 * 3.7854) km/gallon

42.0 km/litre = 158.9868 km/gallon (city)

Next, we convert these to miles/gallon:

183.5919 km/gallon = (183.5919 / 1.6093) miles/gallon

183.5919 km/gallon = 114.08 miles/gallon (highway)

158.9868 km/gallon = (158.9868 /1.6093) miles/gallon

158.9868 km/gallon = 98.79 miles/gallon (city)

3 0
3 years ago
A viscometer may be created by using a pair of closely fitting concentric cylinders and filling the gap between the cylinder wit
kari74 [83]

Answer:

The viscosity of the fluid is 6.05 Pa-s

Explanation:

The viscosity obtained from a rotating type viscometer is given by the equation

\mu =\frac{3Tt}{2\pi \omega R_o(R_o^3-R_i^3)}

where

T is the torque applied in the viscometer

't' is the thickness of gap

\omega is the angular speed of rotation

R_o,R_i are the outer and the inner raddi respectively

Since it is given that

\omega =100rpm=\frac{100\times 2\pi }{60}=10.47rad/sec

Applying the values in the above relation we get

\mu =\frac{3\times 0.021\times 0.02\times 10^{-3}}{2\pi \times 10.47\times 37.5\times 10^{-3}(37.52^3-37.5^3)\times 10^{-9}}=6.04Pa-s

5 0
3 years ago
A car hits a tree at an estimated speed of 10 mi/hr on a 2% downgrade. If skid marks of 100 ft. are observed on dry pavement (F=
Dafna11 [192]

Answer:

v_{o} = 22.703\,\frac{m}{s} \left(50.795\,\frac{m}{s}\right)

Explanation:

The deceleration of the car on the dry pavement is found by the Newton's Law:

\Sigma F = -\mu_{k,1}\cdot m\cdot g \cdot \cos \theta + m\cdot g \cdot \sin \theta = m\cdot a_{1}

Where:

a_{1} = (-\mu_{k,1}\cdot \cos \theta + \sin \theta)\cdot g

a_{1} = (-0.33\cdot \cos 1.146^{\textdegree}+\sin 1.146^{\textdegree})\cdot \left(9.807\,\frac{m}{s^{2}} \right)

a_{1} = -3.040\,\frac{m}{s^{2}}

Likewise, the deceleration of the car on the unpaved shoulder is:

a_{2} = (-\mu_{k,2}\cdot \cos \theta + \sin \theta)\cdot g

a_{2} = (-0.28\cdot \cos 1.146^{\textdegree}+\sin 1.146^{\textdegree})\cdot \left(9.807\,\frac{m}{s^{2}} \right)

a_{2} = -2.549\,\frac{m}{s^{2}}

The speed just before the car entered the unpaved shoulder is:

v_{o} = \sqrt{\left(4.469\,\frac{m}{s} \right)^{2}-2\cdot \left(-2.549\,\frac{m}{s^{2}} \right)\cdot (60.88\,m)}

v_{o} = 18.175\,\frac{m}{s}

And, the speed just before the pavement skid was begun is:

v_{o} = \sqrt{\left(18.175\,\frac{m}{s} \right)^{2}-2\cdot \left(-3.040\,\frac{m}{s^{2}} \right)\cdot (30.44\,m)}

v_{o} = 22.703\,\frac{m}{s} \left(50.795\,\frac{m}{s}\right)

8 0
3 years ago
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