Answer:
![Gs = 1 / (s + 1)^3](https://tex.z-dn.net/?f=%20Gs%20%3D%201%20%2F%20%28s%20%2B%201%29%5E3%20)
Explanation:
A system is known to be a stable system if the poles of the system lie on the negative real axis of the s plane.
A system that could be driven unstable by a P-controller would be:
![Gs = 1 / (s + 1)^3](https://tex.z-dn.net/?f=%20Gs%20%3D%201%20%2F%20%28s%20%2B%201%29%5E3%20)
As the value of K increases, the closed loop poles move into the right half s plane
Answer:
From the main bearings, the oil passes through feed-holes into drilled passages in the crankshaft and on to the big-end bearings of the connecting rod.
Answer:
Check the explanation
Explanation:
beam span = 25 ft
dead load = 0.6 kip/ft
live load = 2.1 kip/ft
factored load = 1.2*0.6 +1.6*2.1=4.08 kip/ft
moment in beam = 4.08*252/8=318.75 kip-ft = 3825 kip-in
design strength =0.9* 50 = 45 ksi
plastic section modulus required = 3825/45=85 in3
Moment in beam in ASD = (0.6+2.1)*252/8 = 210.9 kip-ft
lighest W section from LRFD = W21x44
lightest W section from ASD = W21x44
Answer:
![\mathbf{G_m = 2.25}](https://tex.z-dn.net/?f=%5Cmathbf%7BG_m%20%3D%202.25%7D)
Explanation:
From the given information:
Let the weight of the mix in the air be =
Let the weight of the mix in water be =
; &
the bulk specific gravity be =
SO;
Also;
From (2), make
the subject:
Now, equation (1) can be rewritten as:
Replacing the values;
Answer:
Check the explanation
Explanation:
Code
.ORIG x4000
;load index
LD R1, IND
;increment R1
ADD R1, R1, #1
;store it in ind
ST R1, IND
;Loop to fill the remaining array
TEST LD R1, IND
;load 10
LD R2, NUM
;find tw0\'s complement
NOT R2, R2
ADD R2, R2, #1
;(IND-NUM)
ADD R1, R1, R2
;check (IND-NUM)>=0
BRzp GETELEM
;Get array base
LEA R0, ARRAY
;load index
LD R1, IND
;increment index
ADD R0, R0, R1
;store value in array
STR R1, R0,#0
;increment part
INCR
;Increment index
ADD R1, R1, #1
;store it in index
ST R1, IND
;go to test
BR TEST
;get the 6 in R2
;load base address
GETELEM LEA R0, ARRAY
;Set R1=0
AND R1, R1,#0
;Add R1 with 6
ADD R1, R1, #6
;Get the address
ADD R0, R0, R1
;Load the 6th element into R2
LDR R2, R0,#0
;Display array contents
PRINT
;set R1 = 0
AND R1, R1, #0
;Loop
;Get index
TOP ST R1, IND
;Load num
LD R3,NUM
;Find 2\'s complement
NOT R3, R3
ADD R3, R3,#1
;Find (IND-NUM)
ADD R1, R1,R3
;repeat until (IND-NUM)>=0
BRzp DONE
;load array address
LEA R0, ARRAY
;load index
LD R1, IND
;find address
ADD R3, R0, R1
;load value
LDR R1, R3,#0
;load 0x0030
LD R3, HEX
;convert value to hexadecimal
ADD R0, R1, R3
;display number
OUT
;GEt index
LD R1, IND
;increment index
ADD R1, R1, #1
;go to top
BR TOP
;stop
DONE HALT
;declaring variables
;set limit
NUM .FILL 10
;create array
ARRAY .BLKW 10 #0
;variable for index
IND .FILL 0
;hexadecimal value
HEX .FILL x0030
;stop
.END