Answer:critical stress= 20.23 MPa
Explanation:
Since there was an internal crack, we will divide the length of the internal crack by 2
Length of internal crack, a = 0.7mm,
Half length = 0.7mm/2= 0.35mm changing to meters becomes
0.35/ 1000= 0.35 x 10 ^-3m
The formulae for critical stress is calculated using
σC = (2Eγs /πa) ¹/₂
σC = critical stress=?
Given
E= Modulus of Elasticity= 225GPa =225 x 10 ^ 9 N/m²
γs= Specific surface energy = 1.0 J/m2 = 1.0 N/m
a= Half Length of crack=0.35 x 10 ^-3m
σC= (2 x 225 x 10 ^ 9 N/m² x 1.0 N/m /π x 0.35 x 10 ^-3m)¹/₂
=(4.5 x 10^11/π x 0.35 x 10 ^-3)¹/₂
=(4.0920 x10 ^14)¹/₂
σC=20.23 x10^6 N/m² = 20.23 MPa
Answer:
T=kg·m^2/s^2
Explanation:
T = kg (m^2/s^2) m^3 /m^3
Here I wrote down the unit for every dimension.
T=kg m^2 / s^2
m^3 is divided between m^3, this is equal to 1.
Result: T=kg·m^2/s^2
PD: I'm not sure if this is what you ask for. I hope it helps
Answer:
The change in specific internal energy is 3.5 kj.
Explanation:
Step1
Given:
Total change in energy is 15.5 kj.
Change in kinetic energy is –3.5 kj.
Change in potential energy is 0 kj.
Mass is 5.4 kg.
Step2
Calculation:
Change in internal energy is calculated as follows:
kj.
Step3
Specific internal energy is calculated as follows:
kj/kg.
Thus, the change in specific internal energy is 3.5 kj/kg.
Answer:
6.9
Explanation:
I had the same question lol your welcomr if itd not right in sorry
