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3 years ago

HELP PLEASE ! TYYYY!!!!!!!!!!!!!!!!!!!!!!!!

Engineering

1 answer:

My name is Ann [436]3 years ago

8 0

You can pick the song Cover me in sunshine- By pink

This is a very beautiful song that describes happiness.
I feel happy when I listen to this song because it shows the connection between a mother and daughter.
Also, The song compares Sunshine with Happiness.

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Who wants to play fortnite my name (JayIsABot13)

Blizzard [7]

Answer:

I'll play

Explanation:

I'm insane like so good at it

3 0

3 years ago

Read 2 more answers

A series circuit has 4 identical lamps. The potential difference of the energy source is 60V. The total resistance of the lamps

Alexxx [7]

Answer:

$I=3A$

Explanation:

From the question we are told that:

Number of lamps $N=4$

Potential difference $V=60v$

Total Resistance of the lamp is $R= 20ohms$

Generally the equation for Current I is mathematically given by

$I=\frac{V}{R}$

$I=\frac{60}{20}$

$I=3A$

8 0

3 years ago

A stress of 2500 psi is applied to a polymer serving as a fastener in a complex assembly. At a constant strain, the stress drops

sesenic [268]

Very very hard to answer

6 0

3 years ago

A rigid canister with a radius of 5 in and a height of 10 in is filled with air. The initial pressure and temperature of air in

Elza [17]

Answer:1.458 Btu

Explanation:

Given

radius of canister $\left ( r\right )=5in$

Height of canister $\left ( h\right )=10 in.$

Initial pressure $\left ( P_i\right )=14.7 Psi$

Initia ltemprature $\left ( T_i\right )=70^{\circ}F$

Final pressure $\left ( P_f\right )=30Psi$

as canister is rigid therefore change in volume is zero

therefore

$\frac{P_i}{T_i}$ = $\frac{P_f}{T_f}$

$\frac{14.7}{70}$ = $\frac{30}{T_f}$

$T_f=142.85^{\circ}F$

volume of canister= $\pi \times r^{2}\times h$

= $\pi \times 5^{2}\times 10=250\pi$

volume of canister=12872,038.8 $mm^3$

now calculating mass of air

PV=mRT

substituting values

$\left ( 14.7Psi\right )\left ( 12872,038.8 mm^3\right )=m\left ( 0.287\right )\left ( 70^{\circ}F\right )$

m=21.0192 gm

Therefore heat transferred = $mc_p\left ( T_f-T_i\right )$

= $21.0192\times 10^{-3}\times \left ( 142.857-70\right )$

=1539.052J=1.458Btu

3 0

4 years ago

The alignment readings for the front of a vehicle are shown above. Camber and toe are within specification, caster is not. Techn

dlinn [17]

Answer:

B. B only

Given Information:

1. Camber and toe are within specification

2. Caster is not within specification

Technician A says that with the current settings, the left front tire tread may wear on the inside edge.

Technician B says that with the current settings, the vehicle may pull to the left

Explanation:

Lets discuss the effects of Camber, toe and caster misalignment

Effects of Camber and Toe misalignment:

Camber is the inward or outward tilt of the fron tires and is used to distribute load across the tread. Any misalignment causes uneven loading on the tires which results in tire wear on one edge.

The most common cause of tire wear on the inside edge is due to the camber misalignment which results in premature tire wear.

Another reason is of tire wear is vehicle’s toe. A slight misalignment of the toe reduces the life of the tire.

Since it is given that camber settings and toe settings are within specification therefore, tire tread wear on the inside edge cannot happen if camber and toe are within specification.

Technician A cannot be right.

Effects of Caster misalignment:

Whenever there is a misalignment of the castor then the vehicle will not be able to go in straight line rather it will pull to either left or right side. Caster misalignment also causes heavy or light steering depending upon the positive or negative misalignment of caster.

Since it is given that caster settings are not within specification therefore, the vehicle may pull to the left due to the caster misalignment.

Technician B must be right.

4 0

4 years ago