Answer:
3 3/18
Step-by-step explanation:
5 3/6-2 1/3
We first need to turn our mixed numbers into fractions by multiplying the while number by the denominator, then adding the numerator. When we do this, 5 3/6 turns into 33/6 and 2 1/3 turns into 7/3. Now we have this:
33/6-7/3
Now we need to find the Least common multiple of the denominators in order to find our common denominator, which in this case is 6. 33/6 already has a denominator of 6, so we do not need to do anything to it. To give a denominator of 6 to 7/3, however, we must multiply by 2, giving us this:
33/6-14/6
Now we can subtract the numerators.
19/6
To turn this back into a mixed number, we divide 19 by 6, which gives us 3 with a remainder of 1. Therefore, our answer is 3 1/6. This is an equivalent fraction to the fourth answer, 3 3/18.
HTH :)
Answer:
So, you just end up plugging in your numbers.
y = 28 - 3(1)
y = 28-3
y = 25
Y = 28 - 3(3)
y = 28 - 9
y = 19
y = 28 - 3x
y = 28 - 3(4)
y = 28 - 12
y = 16
y = 28 - 3x
y = 28 - 3(6)
y = 28 - 18
y = 10
Step-by-step explanation:
Answer:
True
(1) You can prove two triangles are similar using AA similarity.
(2)If side length of similar figure have ration 
then the ratio of surface areas will be:
(3)If side length of similar figure have ratio of 
then perimeter will have ratio:.
False:
(1)If side length of similar figure have ration then the ratio of Volumes will be:
(2)If side length of similar figure have ration then the ratio of surface area will be:
Answer:
He got 42,000 subs in the 2 weeks.
Step-by-step explanation:
Since the interest is compounded, we will have to use the compound interest formula.
We Weill plug 7500 in for A, because that's the amount of money that we want to have at the end of some amount of time.
5000 will go in for P because that's the starting amount.
2.7% will be converted into a decimal percentage form. You can do this by dividing by 100, which you will get .027, and then plug that in for r, the rate.
Since the interest is compounded quarterly, n = 4.
After a bit of number crunching, you will get to the point where you have to solve for an exponent. You can easily do this by using the natural log ln(). One property of logarithm is that you can take the exponent and place it in front of the log. Now you can divide both sides to separate and solve for t.
