Answer:
2/9
Step-by-step explanation:
5+4=9
so getting 2 reds is 2/9
Answer:
Please check the explanation.
Step-by-step explanation:
6)
Given ΔMNO ≅ ΔPQR
As congruent parts of congruent triangle are congruent.
and also given
so
m∠N = m∠Q
2x+6 = 4x+12
4x-2x = 6-12
2x = -12
Divide both sides by 2
x = -6
Thus, the value of x = -6
Therefore, option 'A' is true.
7)
Given ΔABC ≅ ΔDEF
As congruent parts of congruent triangle are congruent.
and also given
so
AB = DE
4v+2 = 6v-4
6v-4v = 2+4
2v=6
Divide both sides by 2
v = 3
Thus, the value of v = 3
Therefore, option 'A' is true.
Answer:
B. 4 imaginary; 1 real
Step-by-step explanation:
Given the polynomial:
x^5 + 7*x^4 + 2*x^3 + 14*x^2 + x + 7
it can be reordered as follows
(x^5 + 2*x^3 + x ) + (7*x^4 + 14*x^2 + 7)
Taking greatest common factor at each parenthesis
x*(x^4 + 2*x^2 + 1) + 7*(x^4 + 2*x^2 + 1)
Taking again the greatest common factor
(x + 7)*(x^4 + 2*x^2 + 1)
Replacing x^2 = y in the second parenthesis
(x + 7)*(y^2 + 2*y + 1)
(x + 7)*(y + 1)^2
Coming back to x variable
(x + 7)*(x^2 + 1)^2
There are two options to find the roots
(x + 7) = 0
or
(x^2 + 1)^2 = 0 which is the same that (x^2 + 1) = 0
In the former case, x = -7 is the real root. In the latter, (x^2 + 1) = 0 has no real solution. Therefore, there is only 1 real root in the polynomial.
Answer:
Here is the solution. Hope it helps ☺️
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