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aliya0001 [1]
3 years ago
10

Find the volume of this. Show work.

Mathematics
1 answer:
Yuri [45]3 years ago
6 0

Answer: 471.24 (with 3.14 as pi)

Step-by-step explanation:

Volume of cylinder = pi*r^2*height

Radius = 10/2 = 5

Pi*25^2*6 = 471.24

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3 years ago
Which expression is equivalent to -x² + 5x + 94 = 13?
jolli1 [7]
the correct answer is A.
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Target sells 24 bottles of water for $3, and 36 bottles of water for $4. Which is the better buy and by how much?
madam [21]
First, we need to find the cost per bottle for both offers:

3 / 24 = 0.125$
4 / 36 = 0.11$

(Note: I divided 3 by 24 bc we are spreading the 3 dollars over 24 bottles. If I wanted to find the number of bottles per bottle, I would divide 24 by 3.)

The cheaper per bottle offer is 36 bottles for 4$. The only option for this is D. We can calculate the difference by subtracting 0.11 from 0.125, which is 0.014$ or 1.4¢. Hope that helps!
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3 years ago
solve. 1/3/4+ 7/8 A. 2/1/4 B. 2/5/8 C. 2/3/8 D. 3/1/2
sleet_krkn [62]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Rent and other associated housing costs, such as utilities, are an important part of the estimated costs of attendance at colleg
zhenek [66]

Answer:

96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is  [335.89 , 356.10].

Step-by-step explanation:

We are given that a group of researchers at the BYU Off-Campus Housing department want to estimate the mean monthly rent that unmarried BYU students paid during winter 2018.

During March 2018, they randomly sampled 314 BYU students and found that on average, students paid $346 for rent with a standard deviation of $86.

So, the pivotal quantity for 95% confidence interval for the average age is given by;

           P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = average rent paid by 314 BYU students = $346

            s = sample standard deviation = $86

            n = sample of students = 314

            \mu = population mean monthly rent of all unmarried BYU students

So, 96% confidence interval for the population mean monthly rent, \mu is ;

P(-2.082 < t_3_1_3 < 2.082) = 0.96

P(-2.082 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.082) = 0.96

P( -2.082 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.082 \times {\frac{s}{\sqrt{n} } } ) = 0.96

P( \bar X -2.082 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X +2.082 \times {\frac{s}{\sqrt{n} } } ) = 0.96

96% confidence interval for \mu = [ \bar X -2.082 \times {\frac{s}{\sqrt{n} } } , \bar X +2.082 \times {\frac{s}{\sqrt{n} } } ]

                                                = [ 346 -2.082 \times {\frac{86}{\sqrt{314} } } , 346 +2.082 \times {\frac{86}{\sqrt{314} } } ]

                                                = [335.89 , 356.10]

Therefore, 96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

5 0
4 years ago
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