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lapo4ka [179]
3 years ago
10

I lost my two brain cell trynna work it out pls help lol​ I'll brainlist everyone who have a try at this!!!

Mathematics
2 answers:
lawyer [7]3 years ago
8 0

Answer:

a. 2r=g

b. g-5=b

c. 4+g=b

Jlenok [28]3 years ago
5 0

Answer:

A) r x 2 = g

B) b - 5 = g

C) b x 4 = g

Step-by-step explanation:

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6 0
3 years ago
The area of a rectangle is 14 square units. It has side lengths xxx and yyy. Given each value for xxx, find yyy.
Korolek [52]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Can someone please help me?? Im not quite sure how to get this answer.
nekit [7.7K]

Answer:

C. 54π + 20.25√3 cm²

Step-by-step explanation:

The shaded area can be split into two areas: a sector and an isosceles triangle.

Area of a sector is:

A = (θ/360°) πr²

where θ is the central angle and r is the radius.

Area of an isosceles triangle can be found with SAS formula:

A = ½ ab sin θ

where a and b are two sides of a triangle and θ is the angle between them.

In this case, r = a = b = 9 cm.  The central angle of the sector is 240°, and the vertex angle of the triangle is 120°.  Therefore, the total area is:

A = (240°/360°) π (9 cm)² + ½ (9 cm) (9 cm) sin 120°

A = 54π + 20.25√3 cm²

5 0
3 years ago
In ΔIJK, the measure of ∠K=90°, KJ = 65, IK = 72, and JI = 97. What is the value of the cosine of ∠J to the nearest hundredth?
kow [346]

Answer:

\cos(J) = 0.67

Step-by-step explanation:

Given

\angle K = 90^o

KJ = 65

IK = 72

JI = 97

Required

\cos(J)

The question is illustrated with the attached image.

From the image, we have:

\cos(J) = \frac{KJ}{JI}

This gives:

\cos(J) = \frac{65}{97}

\cos(J) = 0.67010309278

\cos(J) = 0.67 --- approximated

7 0
3 years ago
Help me on this please
ruslelena [56]

Answe65

Step-by-step explanationthat the anews

3 0
2 years ago
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