<span>STP
signifies standard temperature and pressure. This conditions are at 1
atmospheric pressure and 0 degrees Celsius. It has been said that at these
conditions, one mole of a gas molecule is equivalent to 22.4 liters of volume.
Therefore, the correct answer is option B. </span>
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
First equation: A. Combustion
Second equation: C. Decomposition
Third equation: E. Double Replacement
Fourth equation: D. Single Replacement
Fifth equation: B. Synthesis
We place a burning splint at the mouth of the test tube and listen for a pop sound. It occurs because Hydrogen gas is explosive. The third option is correct.
Answer:
1) 2.054 x 10⁻⁴ mol/L.
2) Decreasing the temperature will increase the solubilty of O₂ gas in water.
Explanation:
1) The solubility of O₂ gas in water:
- We cam calculate the solubility of O₂ in water using Henry's law: <em>Cgas = K P</em>,
- where, Cgas is the solubility if gas,
- K is henry's law constant (K for O₂ at 25 ̊C is 1.3 x 10⁻³ mol/l atm),
- P is the partial pressure of O₂ (P = 120 torr / 760 = 0.158 atm).
- Cgas = K P = (1.3 x 10⁻³ mol/l atm) (0.158 atm) = 2.054 x 10⁻⁴ mol/L.
2) The effect of decreasing temperature on the solubility O₂ gas in water:
- Decreasing the temperature will increase the solubilty of O₂ gas in water.
- When the temperature increases, the solubility of O₂ gas in water will decrease because the increase in T will increase the kinetic energy of gas particles and increase its motion that will break intermolecular bonds and escape from solution.
- Decreasing the temperature will increase the solubility of O₂ gas in water will because the kinetic energy of gas particles will decrease and limit its motion that can not break the intermolecular bonds and increase the solubility of O₂ gas.
<h3>Further explanation
</h3>
In general, some people equate mass and weight.
Mass is one of the principal quantities, which is related to the matter , whereas weight is a force that leads to the center of the earth (Earth's gravitational force)
Steps that can be taken to find the mass :
- 1. Weigh graduated cylinder (empty)
- 2. Pour the alcohol in the beaker into the graduated cylinder to the level of 40 ml
- 3. Weigh again graduated cylinder + poured alcohol
- 4. mass of alcohol 40 ml = mass in 3rd step - mass in the first step