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2 years ago

CO 2 is an element. true or false

Chemistry

2 answers:

Step2247 [10]2 years ago

8 0

Answer:

true

Explanation:

co2 is carbon dioxide

Hope this helps.

iren [92.7K]2 years ago

7 0

Answer: false

Explanation:

f this helps typically an element wont have a 2 next to it, to see if something is an element or compound check for the element on the periodic table and see if the structure or name matches the one given to you on the question. for example here it is Co2 on the periodic table it's simply written as Co

co2 or carbon dioxide is a compound not an element, you can even check this on the periodic table

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The coordination number of cation and anion in fluorite CaF2 and antifluorite Na2O are respectively

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3 years ago

During the naval battles of the South Pacific in World War II, the U.S. Navy produced smoke screens by spraying titanium tetrach

hammer [34]

Explanation:

The reaction given is;

TiCl4 + H2O --> TiO2 + HCl

The reaction is not balanced, upon balancing it is given as;

TiCl4 + 2H2O → TiO2 + 4HCl

a. How many moles of H2O are needed to react with 6.50 moles of TiCl4?

From the reaction;

1 mol of TiCl4 requires 2 mol of H2O

6.50 mol of TiCl4 would require x mol of H2O

1 = 2

6.5 = x

x = 6.5 * 2 / 1 = 13.0 mol

b. How many moles of HCl are formed when 8.44 moles of TiCl4 react?

From the equation of the reaction;

1 mol of TiCl4 reacts to form 4 mol of HCl

8.44 mol of TiCl4 reacts to form x mol of HCl

1 = 4

8.44 = x

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3 years ago

Most enzymes work best at 37C because at lower and higher temperatures, the conditions are not optimal for their performance. Ex

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2 years ago

Chlorine gas is added to a large flask to a pressure of 1.85 atm, at a temperature of 322 K. Phosphorus is added, and a reaction

AVprozaik [17]

Answer:

The volume of the flask is 20.245 litres .

Explanation:

We are given with following information-

$PV=nRT$ -------- 1

where R = $0.0821L.atom/mole.K$

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The given chemical equation is -

$2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5 _(_s_)$ --------- 2

Now , calculation -

Mass of $PCl_5$ formed = 118g

Molar mass of $PCl_5$ = $208.22g/mole$

Mole = $\frac{mass (g)}{molar mass}$

Therefore , moles of $PCl_5$ formed = $\frac{118}{208.22}$

From equation 2 , we get to know that ,

2mole $PCl_5$ formed from 5 mole $Cl_2 _(_g_)$

Therefore , $\frac{118}{208.22}$ mole $PCl_5$ formed from $\frac{5}{2} \times\frac{118}{208.22}$ mole $Cl_2 _(_g_)$

Moles of $Cl_2 _(_g_)$ used = $\frac{5\times118}{2\times208.22} mole$

R= $0.0821L.atom/mole.K$

Pressure (P)= 1.85atm

Temperature (T)= 322K

Moles of $Cl_2 _(_g_)$ (n)= $\frac{5}{2} \times\frac{118}{208.22}$ moles

Applying the formula above in 1 equation , that is

PV = nRT

putting the given values -

$1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322$

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