Question

An independent random sample is selected from an approximately normal population with an unknown standard deviation. Find the p-value for the given set of hypotheses and _t_ statistic. Also determine if the null hypothesis would be rejected at $\alpha$

Answer 1

The complete question is missing, so i have attached it

Answer:

A) Reject the null hypothesis

B) Reject the null hypothesis

C) Fail to reject the null hypothesis

D) Reject the null hypothesis

Step-by-step explanation:

A) We are given;

Ha: μ > μ_o (This is thus, a one-tail problem)

n = 11

T = 1.91

Using online p-value from t-score calculator as attached with a DF = n - 1 = 11 - 1 = 10, and t-value = 1.91, and significance level of 0.05, and 1 tail, we have;

The p-value is 0.042602

P-value is less than significance level, thus, we will reject the null hypothesis

B) We are given;

Ha: μ < μ_o (This is thus, a one-tail problem)

n = 17

T = -3.45

Using online p-value from t-score calculator as attached with a DF = n - 1 = 17 - 1 = 16, and t-value = 1.91, and significance level of 0.05, and 1 tail, we have;

The p-value is  0.001647

P-value is less than significance level, thus, we will reject the null hypothesis

C)We are given;

Ha: μ ≠ μ_o (This is thus, a two-tail problem)

n = 7

T = 0.83

Using online p-value from t-score calculator as attached with a DF = n - 1 = 7 - 1 = 6, and t-value = 0.83, and significance level of 0.05, and 2 tail, we have;

The p-value is 0.438308.

P-value is higher than the significance level, thus, we will fail to reject the null hypothesis.

D) We are given;

Ha: μ > μ_o (This is thus, a one-tail problem)

n = 28

T = 2.13

Using online p-value from t-score calculator as attached with a DF = n - 1 = 28 - 1 = 27, and t-value = 2.13, and significance level of 0.05, and 1 tail, we have;

The p-value is 0.021218

P-value is lower than the significance level, thus, we will reject the null hypothesis

P-value is lower than the significance level, thus, we will reject the null hypothesis.