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s2008m [1.1K]
3 years ago
7

The mean of a normal probability distribution is 460; the standard deviation is 18.About 68% of the observations lie between wha

t two values?About 95% of the observations lie between what two values?Practically all of the observations lie between what two values?
Mathematics
1 answer:
blsea [12.9K]3 years ago
8 0
<h2>Answer with explanation:</h2>

As per given , we have

\mu=460 , \sigma= 18

  • According to the empirical rule , about 68% of the population lies within 1 standard deviation from mean :-

i.e. About 68% of the observations lie between (\mu-1(\sigma) and \mu+1(\sigma))

i.e. About 68% of the observations lie between (460-1(18) and 460+1(18))

About 68% of the observations lie between<u> 442</u> and <u>478</u>.

  • Again , according to the empirical rule , about 95% of the population lies within 2 standard deviations from mean :-

i.e. About 95% of the observations lie between (\mu-2(\sigma) and \mu+2(\sigma))

i.e. About 95% of the observations lie between (460-2(18) and 460+2(18))

About 95% of the observations lie between <u>424</u> and <u>496</u>.

  • Also, Practically all of the observations(99.7%) lie between lies within 3 standard deviations from mean :-

i.e. Practically all of the observations lie between (\mu-3(\sigma) and \mu+3(\sigma))

i.e. Practically all of the observations lie between (460-3(18) and 460+3(18))

Practically all of the observations lie between <u>406</u> and <u>514</u>.

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