Answer:
<h2>I need only 5 brainlisted please give me</h2>
Step-by-step explanation:
<h3>please anyone please I request you all</h3>
Answer: x = 2 degrees Fahrenheit
Step-by-step explanation:
5-3= 2 it’s a pretty simple equation
Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,

or, 
or, 
or, 
or, 
Substituting the value of
in ∠QPR we get,
∠QPR = 
or, ∠QPR = 
Hence,
The value of ∠QPR is 40°.
Answer:
(D) y³ - 8y² +8y +5
Step-by-step explanation:
y³ - 6y²+ 5y - (2y²- 3y - 5 ) = y³ - 6y² + 5y - 2y² + 3y +5 = y³ - 8y² +8y +5
Remember that the radicand (the area under the root sign) must be positive or zero for a radical with an even index (like the square root or fourth root, for example). This is because two numbers squared or to the fourth power, etc. cannot be negative, so there are no real solutions when the radicand is negative. We must restrict the domain of the square-root function.
If the domain has already been restricted to

, we can work backwards to add 11 to both sides. We see that

must be under the radicand, so the answer is
A.