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alexgriva [62]
2 years ago
12

Ruben put an empty cup underneath a leaking faucet. After hours, Ruben had collected cup of water. What is the rate, in cups per

hour, at which the water is leaking from the faucet.
Mathematics
2 answers:
Natalija [7]2 years ago
6 0

Complete question :

Ruben put an empty cup underneath a leaking faucet. After 1 1\2 hours, Ruben collected 1/4 cup of water. What is the rate, in cups per hour, at which the water is leaking from the faucet?

Answer:

1/6 cups per hour

Step-by-step explanation:

Given that :

Time = 1 1/2 hours = 1.5 hours

Cups of water collected = 1/4 cups

Rate in cups per hour :

Cups collected / time

1/4 ÷ 1 1/2

1/4 ÷ 3/2

1/4 * 2/3

= 2/12

= 1/6 cups per hour

7nadin3 [17]2 years ago
3 0

Answer:

1/6 cups per hour

Step-by-step explanation:

Complete question :

Ruben put an empty cup underneath a leaking faucet. After 1 1\2 hours, Ruben collected 1/4 cup of water. What is the rate, in cups per hour, at which the water is leaking from the faucet?

Step-by-step explanation:

Given that :

Time = 1 1/2 hours = 1.5 hours

Cups of water collected = 1/4 cups

Rate in cups per hour :

Cups collected / time

1/4 ÷ 1 1/2

1/4 ÷ 3/2

1/4 * 2/3

= 2/12

= 1/6 cups per hour

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2 years ago
Please help. 10 points. Please do not guess. Guesses will be reported. Thanks
Allushta [10]

The intersecting secant-tangent theorem says that

AP^2=PT\cdot TO

where T is the point at which line segment PO touches the circle. Similarly,

BP^2=PT\cdot TO

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AP^2=BP^2\implies AP=BP

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8 0
3 years ago
What is the perimeter of the polygon?
mr_godi [17]
Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
Thus to find the perimeter, we add up all the sides to get
sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B




6 0
3 years ago
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