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jek_recluse [69]
3 years ago
11

Slope of (-11,5) (-8,4)

Mathematics
1 answer:
nika2105 [10]3 years ago
6 0
Slope is equal to the change in y over change in x, or rose over run m= 1/3
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Order each set of numbers from least to greatest.<br><br><br> PLZ HELP ASAP
Wittaler [7]

Answer:

<h3><u>7. Ans ;</u></h3>

\frac{41}{3}  < 14 <  \sqrt{200}

<h3><u>8</u><u>.</u><u> </u><u>Ans</u><u> </u><u>;</u></h3>

<u>0.6 <  \frac{2}{3}  <  \sqrt{ \frac{9}{16} }</u>

Step-by-step explanation:

<h3><u>7. Ans ;</u></h3>

\sqrt{200}  = 10 \sqrt{2}  = 14.1 \\ 14 = 14 \\  \frac{41}{3}  = 13.6

So ;

\frac{41}{3}  < 14 <  \sqrt{200}  \\ 13.6 < 14 < 14.1

<h3><u>8. Ans ;</u></h3>

\frac{2}{3}  = 0.66 \\  \sqrt{ \frac{9}{16} }   =   \frac{3}{4}  = 0.75 \\ 0.6 = 0.6

So ;

0.6 <  \frac{2}{3}  <  \sqrt{ \frac{9}{16} }  \\ 0.6 < 0.66 < 0.75

I hope I helped you^_^

6 0
2 years ago
HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

45

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

5 0
3 years ago
Order from greatest to least 1.202;1.29;1.02
Reptile [31]

Answer:

1.29, 1.202, 1.02

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A garden is in the shape of a rectangle. If the garden has a length of 4 feet and a width of 6 feet, what is the area of the gar
julsineya [31]

A=lw = 6 \times 4 = 24 \:  {ft}^{2}

5 0
3 years ago
The 6th term of a gp is -2/29,and it's first term is 18.what is the common ratio​
Ymorist [56]

Answer:

-0.329

Step-by-step explanation:

The formula for Geometric ratio is

an = ar^n - 1

Where

a = First term = 18

r = Common ratio = ?

n = Number of term= 6

Hence

a6 = 18 × r^6-1

From the question

a6 = -2/29

Hence:

-2/29 = 18 × r^6-1

-2/29 = 18 × r⁵

Divide both sides by 18

-2/29 ÷ 18 = 18 × r⁵/18

-2/29 × 1/18 = r⁵

r⁵ = -1/261

Take the fifth root of both sides

⁵√(r⁵) = ⁵√(-1/261)

r = -0.3286032834

Approximately = -0.329

Therefore, Common ratio = -0.329

7 0
3 years ago
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