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Harrizon [31]
4 years ago
10

2(x+14)+(2x-14)= do you know this

Mathematics
1 answer:
denis-greek [22]4 years ago
6 0
Yes i do 4x+14 will be final answer 
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If one of the equal sides of an isosceles triangle is five units long, what is the perimeter of the triangle?
Sergio039 [100]

An isosceles triangle has 2 sides of the same length and they are in this case 5 units long so 5+5 and then we can only assume that the 3 side is 3-2 units long since we don’t have an approximate length

4 0
4 years ago
Evaluate (-y)^2 and -y^2 when y=2/5 and when y=-2/5
monitta

Answer:

When y=2/5

(-y)^2= 4/25 and -y^2 = 4/25

When y =-2/5

(--2/5)^2 = 4/25 and -y^2 =4/25

Step-by-step explanation:

6 0
3 years ago
What is the factored form of 2x2 + x-3?
Vesnalui [34]

Answer:

Step-by-step explanation:

a = 2, b = 1, c = -3

We need to factor this by finding the product of a and c, then from there find which factors of a * c will either add or subtract to give us b.

a * c = 6  and the factors of 6 and 1 and 6, 2 and 3.  Well, 6 - 1 doesn't equal 1 and neither does 6 + 1.  So our factors are 3 and 2.  In order to combine those to get a 1 (our b), we will subtract 2 from 3 since 3 - 2 = 1.  That means that 3 is positive and 2 is negative.  Filling in the formula with 3 and 2 in place of 1 looks like this (always remember to put the absolute value of the largest number first):

2x^2+3x-2x-3=0

Group the first 2 terms together and the second 2 term together in order to factor:

(2x^2+3x)-(2x-3)=0 and factor out what's common in each set of parenthesis.

x(2x+3)-1(2x+3)=0

Notice that when we factor out a -1 from the second set of parenthesis, we can distribute it back in to get the equation we started with.  We know that factoring by grouping "works" if what is inside both sets of parenthesis is exactly the same.  Ours are identical: (2x + 3).  That is common now, and can be factored out:

(2x+3)(x-1)=0

That matches your first choice

6 0
3 years ago
The total revenue from the sale of x stereos is given by upper r left parenthesis x right parenthesis equals 3 comma 000 left pa
bija089 [108]
For this case we have the following equation:
 r (x) = 3000 (1-x / 700) ^ 2
 
 We must find the derivative of this function.
 The derivative of the function represents the marginal average revenue.
 We have then:
 r '(x) = 6000 (1-x / 700) * (- 1/700)
 
 Simplifying:
 r '(x) = - (60/7) (1-x / 700)
 
 Answer:
 
the marginal average revenue is:
 r '(x) = - (60/7) (1-x / 700)
6 0
4 years ago
A schoolteacher would like to know whether or not toothpaste brands are used differentially in her classroom (in other words, is
sesenic [268]

Answer:

Step-by-step explanation:

a. What test is appropriate for this analysis?

A Chi-square  test of independence is appropriate for this analysis because it is used to compare two variables or testing relationship on categorical variables.  

b. State the null hypothesis:

The null hypothesis is the default hypothesis

\mathtt{H_o:} There is no particular preference for any brand of toothpaste among students.

c. State the alternative hypothesis:

The alternative hypothesis is the research hypothesis which comes in place to challenge the validity of the null hypothesis.

\mathtt{H_a:} There is particular preference for brands of toothpaste among students.

d. Find the critical value:

degree of freedom = n-1

degree of freedom = 3 - 1

degree of freedom = 2

At the level of significance ∝ = 0.05

The confidence interval = 0.95 and degree of freedom = 2, the critical value from the chi-square distribution table = 5.991

e. Calculate the test statistic:

Using the chi square test statistics; we have the following:

Crest             Colgate            Aquafresh            Total

24                        13                     8                      45

Since we have three brands. Then, for each brand, the expected value

= Total /3

= 45/3

=15

Thus:

Chi -square \mathtt{X^2 = \dfrac{(observed  \ value - expected  \ value)^2}{expected \ value}}

\mathtt{X^2 = \dfrac{(24 - 15)^2}{15}  +  \dfrac{(13 - 15)^2}{15}   + \dfrac{(8 - 15)^2}{15}  }

\mathtt{X^2 = \dfrac{81}{15}  +  \dfrac{4}{15}   + \dfrac{49}{15}  }

\mathtt{X^2 = \dfrac{81+4+49}{15}}

\mathtt{X^2 = \dfrac{134}{15}}

\mathtt{X^2 =8.93  }

f. Make a decision:

Since the chi-square value is greater than the critical value , we reject the null hypothesis and conclude that the students have  particular preference for brands of toothpaste.

8 0
3 years ago
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