Let d = number of dimes, q = number of quarters
<span>Sally has 20 coins in her piggy bank, so </span>
<span>d + q = 20 </span>
<span>The total amount of money is $3.05. </span>
<span>Use the value of each coin multiplied by its number to get total value </span>
<span>.10d + .25q = 3.05 </span>
<span>multiply everything by 100 to clear the decimal places </span>
<span>10d + 25q = 305 and </span>
<span>d + q = 20 </span>
<span>solve the second equation above in terms of either d or q - lets do d </span>
<span>d = 20 - q </span>
<span>sub that into the first equation </span>
<span>10d + 25q = 305 </span>
<span>10(20 - q) + 25q = 305 </span>
<span>200 - 10q + 25q = 305 </span>
<span>15q = 105 </span>
<span>q = 105/15 = 7 </span>
<span>and from above </span>
<span>d = 20 - q = 20 - 7 = 13 </span>
<span>so, there are 13 dimes and 7 quarters </span>
<span>verify with orig problem </span>
<span>13 + 7 = 20, OK, and $1.30 + $1.75 = $3.05
</span>
Answer:
The m∠YXW is 125°.
Addition equation: m∠YXW = m∠YXZ + m∠ZXW = 85° + 40° = 125°
Step-by-step explanation:
To find the m∠YXW you would need to add the m∠YXZ and m∠ZXW together:
m∠YXW = m∠YXZ + m∠ZXW = 85° + 40° = 125°
Fifty one billion six hundred thirty four million seven hundred three thousand and one
The probability that a three shows on at least one of the dice is 11/36.
<h3>How to calculate the probability?</h3>
It should be noted that of probability means the likelihood of the occurence of an event.
The probability that a three shows on at least one of the dice will be:
= 11/36
This can be seen from the table that is attached.
The probability that the total is less than 8 will be:
= 21/36
= 7/12
Here, there are 21 places where the total is less than 8.
Learn more about probability on:
brainly.com/question/24756209
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