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pogonyaev
3 years ago
15

Write the following equation in the general form

Mathematics
1 answer:
shtirl [24]3 years ago
6 0
<h2>Explanation:</h2>

As I understand, the given equation is:

5 y = x-1

So we need to write this into general form. The general form of the equation of a line is given by:

Ax + By + C = 0

Where A and B can't be zero at the same time. So subtracting 5y from both sides:

5y-5y = x-1-5y \\ \\ 0=x-1-5y \\ \\ \\ Arranging: \\ \\ \boxed{x-5y-1=0} \\ \\ \\ So: \\ \\ A=1 \\ \\ B=-5 \\ \\ C=-1

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Is f(x)=x^2-2x+3 a quadratic function
Sav [38]

Answer:

yes

Step-by-step explanation:

A quadratic function has the general form

fx) = ax² + bx + c ( a ≠ 0 )

f(x) = x² - 2x + 3 ← is in this form and is a quadratic function

6 0
3 years ago
Read 2 more answers
Who do you do the problem 7/9+1/7+3/5? please explain thoroughly.
Evgen [1.6K]
To add fractions you want to make sure that the bottom numbers are the same so we have to make them the same, but we have to make sure that the fractions are unchanged so we get the correct answer

so if we find out what number that 9,7, and 5 can all multiply into. we find that 9 times 7 times 5 or 315 is the number that will work

so to get them to all be over 315, we must multiply each fraction by a form of 1/1 or x/x or (number)/(same numbe as on top)

so 7/9 times (35/35)=245/315
1/7 times (45/45)=45/315
3/5 times (56/56)=168/315

we add them togther
245/315+45/315+168/315=(245+45+168)/315=458/315
this simplifies to 1 and 143/315
4 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE!!!
Dafna1 [17]
Answer c or $31.08 is correct:)
5 0
3 years ago
Read 2 more answers
Determine the ordered pair that satisfies the equation, -5x - 6y = -8.
ololo11 [35]
The ordered pair is idk
3 0
3 years ago
Joe began to increase the speed of his car at 2:00 P.M. Since that time,the speed of Joes car has been steadily increasing by 1
Olegator [25]

Answer:

7 mins

Step-by-step explanation:

Current speed of Joes Car = 65.5 mph

We have to find the time interval for which the car exceeded the speed limit of 55 mph.

While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph

We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence

1.50 mph is increased in 1 minute

1 mph will be increase in \frac{1}{1.5} minutes

Hence

10.50 mph will be increased in \frac{1}{1.5} \times 10.50 minutes

= \frac{10.5}{1.5}

=7

Hence joes car was exceeding the limit of 55 mph for 7 minutes.

8 0
3 years ago
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