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2 years ago

Determine the complement and/or supplement of each angle. If it is not possible, explain.

Mathematics

1 answer:

Alecsey [184]2 years ago

3 0

Answer:

complement: 32.8°
supplement: 122.8°

Step-by-step explanation:

The sum of an angle A and its complement C is 90°:

A + C = 90°

C = 90° -A . . . . . subtract A from both sides.

That is, the complement of an angle is found by subtracting the angle from 90°.

The sum of an angle and its supplement is 180°. This means the supplement of an angle is found by subtracting the angle from 180°. You may notice the supplement is 90° more than the complement.

A + S = 180°

S = 180° -A = 90° +(90° -A)

For the given angle, the complement is ...

C = 90° -57.2° = 32.8°

And the supplement is ...

S = 180° -57.2° = 122.8°

_____

<em>Additional comment</em>

We generally like angle measures to be positive (as with all measures in geometry). Hence, we might say that the complement of an angle greater than 90° does not exist. YMMV

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3 years ago

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Answer:

we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

Step-by-step explanation:

Given the expression

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}$

$=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}$

cancel the common factor: 2

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cancel the common factor: p

$=\frac{2p+1}{p^2\left(4p^2-1\right)}$

$=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}$

cancel the common factor: 2p+1

$=\frac{1}{p^2\left(2p-1\right)}$

Expanding

$=\frac{1}{2p^3-p^2}$

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$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

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3 years ago

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Answer:

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2 years ago

a parking garage has 6 levels. Each level has 15 row. Each row has the same number of parking spaces. there are 2,250 parking sp

Mandarinka [93]

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To check this answer we can do

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3 years ago

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