Taking over his thoughts is the answer
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
So we have:
xk = v + w solve for x
divide both sides by k to isolate the variable x:
x = (v+w)/k
^^This is your answer!
Hope I helped!
Answer:
D. A rectangle and an isosceles triangle
Step-by-step explanation:
In the figure attached, the sign is shown. There we can see an arrow, which can be decomposed into a rectangle (on the left of the figure) and an isosceles triangle (on the right of the figure)
Answer:
9.8x + 1.1y + 9.9z
Step-by-step explanation:
⇒ 5.5x + 6.2y + 4.3x + 8.3z + 1.6z - 5.1y
⇒ 9.8x + 1.1y + 9.9z
