Answer:
3960.4 bacteria
Step-by-step explanation:
The formula to solve the above question is given as:
P(t) = Po (2) ^t/k
P(t) = Population after time t = ?
Po = Initial population = 650 bacteria
t = Time in days = 7.3 days
k = doubling time = 2.8 days
P(t) = 650 × (2)^7.3/2.8
P(t) = 650 × 2^2.6071428571
P(t) = 650 × 6.0929582599
P(t) = 3960.4228689 bacteria.
Approximately = 3960.4 bacteria
Therefore, the number of bacteria the researcher will have after 7.3 days if they started with 650 bacteria is 3960.4 bacteria.
Answer:
30 x 5x
9x + 5y
8x+ 20y
Step-by-step explanation:
Answer:
i will help in a bit
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i will help in a bit
Step-by-step explanation:
Answer:
Answers for 1-126
Step-by-step explanation:
a. x + 8 = 21
-8 -8
x = 13
b. x - 32 = 55
+32. +32
x = 87
c. 3x = 54
÷3. ÷3
x = 18
d. x/5 = 10
×5. ×5
x = 50
Answer for 1-124
1/5 = 2/10 , so 2 of the 10 colors are blue and 3 of the 10 colors are green.
The probability is 5/10 = 1/2
this is all I could do. sorry
Answer:
-6
Step-by-step explanation:
13+(-19) (distribute "+" sign into parentheses)
= 13-19
= -6