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Nezavi [6.7K]
3 years ago
15

(25 points) A car rental company's standard charge includes an initial fee plus an additional fee for each mile driven. The stan

dard charge S (in dollars) is given by the function S = 0.40M + 15.75, where M is the number of miles driven.
The company also offers an option to insure the car against damage. The insurance charge I (in dollars) is given by the function I = 0.25M + 3.90.

Let C be the total charge (in dollars) for a rental that includes insurance. Write an equation relating C to M. Simplify your answer as much as possible.

C =
Mathematics
1 answer:
zimovet [89]3 years ago
7 0

Answer:

C = 0.65M+19.65

Step-by-step explanation:

Given the the standard charge S (in dollars) given by the function

S = 0.40M + 15.75, where M is the number of miles driven.

Also the insurance charge I (in dollars) is given by the function

I = 0.25M + 3.90

If C is the total charge (in dollars) for a rental that includes insurance, then:

C = S + I

Substitute the given function into the expression:

C = 0.40M + 15.75 + 0.25M + 3.90

Collect like terms

C = 0.40M+0.25M+15.75+3.90

C = 0.65M+19.65

<em>Hence an equation relating C to M is expressed as C = 0.65M+19.65</em>

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The magnitude and direction of line UV is 19.7° South of West for 8.1 miles

<h3>How to find the magnitude of the vector line UV?</h3>

The magnitude of the vector line UV is given by the length of the line UV,

d = √[(x₂ - x₁)² + (y₂ - y₁)²] where

  • (x₁, y₁) = (2, 3) and
  • (x₂, y₂) = (-2, -4)

Substituting the values of the variables intot he equation, we have

d = √[(x₂ - x₁)² + (y₂ - y₁)²]

d = √[(-2 - 2)² + (-4 - 3)²]

d = √[(-4)² + (-7)²]

d = √[4² + 7²]

d = √[16 + 49]

d = √65

d = 8.06 miles

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So, the magnitude of vector line UV is 8.1 miles

<h3>How to find the direction of the vector line UV</h3>

The direction of the vector line UV is given by Ф = tan⁻¹[(y₂ - y₁)/(x₂ - x₁)] where

  • (x₁, y₁) = (2, 3) and
  • (x₂, y₂) = (-2, -4)

Substituting the values of the variables into the equation, we have

Ф = tan⁻¹[(y₂ - y₁)/(x₂ - x₁)]

Ф = tan⁻¹[(-4 - 3)/(-2 - 2)]

Ф = tan⁻¹[(-7)/(-4)]

Ф = tan⁻¹[7/4]

Ф = tan⁻¹[1.75]

Ф = 60.26°

Ф ≅ 60.3°

Its bearing from the north-south line is α = 90° - Ф

= 90° - 60.3°

= 19.7°

So, its direction is 19.7° South of West

So, the magnitude and direction of line UV is 19.7° South of West for 8.1 miles

Learn more about vectors here:

brainly.com/question/26700114

#SPJ1

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