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Andrei [34K]
2 years ago
7

A student wants to prove the concept of limiting reactants to his lab group during class. If the student adds 56 g or Fe to 71 g

of Cl2, what will the likely result of the reaction be in regards to limiting/excess reactants?
Chemistry
1 answer:
Alexeev081 [22]2 years ago
7 0

The result of the reaction will be such that Cl2 is limiting in its availability

<h3>Limiting reactants</h3>

From the equation of the reaction:

2Fe + 3Cl2 ---> 2FeCl3

Mole ratio of Fe and Cl2 = 2:3

Mole of 56 g of Fe = 56/56 = 1

Mole of 71 g of Cl2 = 71/71 = 1

Whereas, 1 mole of Fe requires 1.5 moles of Cl2. Thus, Cl2 is limiting in availability.

More on limiting reactants can be found here: brainly.com/question/14225536

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An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0
Vlad [161]

Answer:

1.2 atm

Explanation:

Given data

  • Volume of the gas in the tank (V₁): 200.0 L
  • Pressure of ethylene gas in the tank (P₁): ?
  • Volume of the gas in the torch (V₂): 300 L
  • Pressure of the gas in the torch (P₂): 0.8 atm

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm

3 0
3 years ago
a) A table tennis ball has been hit is about 13.16 times as fast as the speed for the swimming. What is the speed of the table t
Alex

x=swimming

The answer is X*13.16

7 0
3 years ago
certain gas occupies 6.24L at pressure of 760 mm Hg.If the pressure is reduced to 60.0mm Hg,what would the new volume be?​
vovikov84 [41]

Answer:

79.04 L

Explanation:

We are given;

Initial Volume; V1 = 6.24L

Initial Pressure; P1 = 760 mm Hg

Final pressure; P2 = 60.0mm Hg

To solve for final volume, we will use Boyles law;

P1•V1 = P2•V2

Let's make V2 which is the final volume the subject;

V2 = (P1•V1)/P2

V2 = (760 × 6.24)/60

V2 = 79.04 L

3 0
2 years ago
Na + Cl --&gt; NaCl
dalvyx [7]

Answer:

38.152 g NaCl would be produced.

Explanation:

\frac{(23 + 35.5) \times 15}{23}  \\  = 38.152 \:  \: g

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5 0
2 years ago
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How many molecules of carbon tetrafluoride, CF4, are in 176 grams of CF4?
RUDIKE [14]

Answer:

1.2*10^24 molecules of CF4

Explanation:

the molar mass of cf4 is 88.0043 g/mol

176/88.0043 = 2 moles of CF4

Then multiply by avogadro's number (6.022*10^23) to get the number of molecules

2*6.022*10^23 = 1.2*10^24 molecules of CF4

5 0
2 years ago
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