Question

Find the distance between line 11x-60y-15=0 and point (2, 1/60)

Answer 1

Answer:

The answer to your question is: d = 6 / 61 or 0.1 units

Step-by-step explanation:

Data

Line: 11x - 60y - 15 = 0   A = 11; B = -60; C = -15

Point (2, 1/60)                 x = 2    y = 1/60

Formula

d = | Ax + By + C | / √(A² + B²)

Process

d = | (11)(2) + (-60)(1/60) -15 | / √(11² + (-60²)

d = | 22 -1 - 15 | / √ 121 + 3600

d = | 6 | / √3721

d = | 6 | / 61

d = 6 / 61 or 0.1 units

Answer 2

Replace x and y

(2, 1/60)
2 is your x and 1/60 is your y. You want to plug those into the equation to get your distance.

11x-60y-15=0

Solving for Y:

11(2) -60y-15=0
22 - 60y - 15 = 0
-22. -22
--------------------------
60y - 47 = 0
+47. +47
---------------------------
60y = 47
---------------
60

y = .78

- do the same for x and graph your point if asked