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Gemiola [76]
3 years ago
11

PLEASEEE HELPPPPPP I bed help

Mathematics
1 answer:
LenaWriter [7]3 years ago
7 0

Answer:

9 orders of nachos.

Step-by-step explanation:

n = orders of nachos

6.25n+5.75=62\\6.25n=56.25\\n=9

Therefore, Jarod can order 9 orders of nachos.

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Three hours ahead of ten forty in the morning
VashaNatasha [74]
It's one forty PM in the afternoon (just look at a clock)
6 0
3 years ago
Read 2 more answers
Kelsey graphed the equation y = 3x + 1 as shown below.
USPshnik [31]

Answer:

D. Kelsey graphed the slope as the y-intercept and the y-intercept as the slope.

Step-by-step explanation:

The equation to graph was : y= 3x + 1 where the slope is 3 and the y-intercept is 1

However, Kelsey graph line passes through points (-3, 0)and (0, 3).From these points the equation of the line is;

m=Δy/Δx  where

m=the slope of the graph

Δy= 3-0 =3

Δx= 0--3 =3

m=3/3 = 1

The equation of the line should be;

m=Δy/Δx

1=y-3/x-0

1x= y-3

3+1x= y

y= 1x + 3 ----------where the slope is 1 and y-intercept is 3

So you can see here that in the original equation,<em> the slope m is 3 and y-intercept is 1 as shown in the first attached graph.</em>

While in the Kelsey's graph, <em>the slope is 1 and the y-intercept is 3 as in the second attached graph. </em>

<em>Thus, the correct answer is D : Kelsey graphed </em><u><em>the slope,3</em></u><em> as the </em><em>y-intercept </em><em>and the</em><u><em> y-intercept,1,</em></u><em> as the slope. </em>

Answer choice A is incorrect because Kelsey didnot graph the y-intercept, 1 on the x-axis but graphed point (-3,0) on the x-axis.

Answer choice B is incorrect because on Kelsey's equation the y-intercept is 3 and not -3. i.e. y=1x + 3

Answer choice C is incorrect because Kelsey graphed the slope as up 1 right 1 which is okay per the equation , y=1x+3.However, this incorrect because the correct graph has a slope of 3.

4 0
3 years ago
Read 2 more answers
The following table shows Jace's earnings based on the number of hours that he works.
statuscvo [17]

Answer:

no

Step-by-step explanation:

because no

7 0
1 year ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
3 years ago
The table shows values for functions f(x)and g(x)
sweet-ann [11.9K]

Answer:

x= -1 and x =0

Step-by-step explanation:

all work is shown and pictured

6 0
3 years ago
Read 2 more answers
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