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Gnoma [55]
3 years ago
14

Evan bought a book on training for a triathlon. The book cost $13.95. He gave the cashier a $20 bill. How much

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
5 0
6.05 is how much change Evan received
strojnjashka [21]3 years ago
3 0

Answer: He received $6:05.

Step-by-step explanation:

I got this by subtracting $13.95 from $20.00.

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What value must k take in order for the following expression to be greater than zero?
svetlana [45]

Basically anything greater than zero...k>0

8 0
3 years ago
Which object has the mass of about one kilogram?
Step2247 [10]

Answer:

A book about a mass of 1 kilogram, but that isn't the only answer.

Explanation:

There's many objects with a mass of one kilogram like one liter of water, a pineapple, bag of sugar etc.

7 0
3 years ago
Gustavo's bicycle cost $171.18 after a sales tax of 8%. write and solve an equation to find the price of the bike before the sal
Kryger [21]
Let x =  price of the bike before a sales tax.

The price after a sales tax of 8% is
x + 0.08x = 1.08x dollars

Because the price paid was $171.18, therefore
1.08x = 171.18
x = 171.18/1.08 = $158.50

Answer: 158.50


3 0
4 years ago
A local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. In o
Mandarinka [93]

Answer:

(a) Null Hypothesis, H_0 : \mu = 22 ounces  

    Alternate Hypothesis, H_A : \mu\neq 22 ounces

(b) The value of the test statistic is -2.687.

(c) The critical values are -1.96 and 1.96.

(d) We conclude that Reject H_0 since the value of the test statistic is less than the negative critical value.

Step-by-step explanation:

We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle.

He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.

<em>Let </em>\mu<em> = average ounces of passion fruit juice used to fill each bottle.</em>

(a) So, Null Hypothesis, H_0 : \mu = 22 ounces     {means that the average of 22 ounces of passion fruit juice is used to fill each bottle}

Alternate Hypothesis, H_A : \mu\neq 22 ounces     {means that the average different from 22 ounces of passion fruit juice is used to fill each bottle}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                        T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean weight of the passion fruit juice = 21.54 ounces

            \sigma = population standard deviation = 1.38 ounce

            n = sample of bottles = 65

So, <u><em>test statistics</em></u>  =  \frac{21.54-22}{\frac{1.38}{\sqrt{65} } }  

                               =  -2.687

(b) The value of z test statistics is -2.687.

(c) Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that Reject H_0 since the value of the test statistic is less than the negative critical value which means that the average different from 22 ounces of passion fruit juice is used to fill each bottle.

6 0
3 years ago
This is the image yall were asking for
Lubov Fominskaja [6]

Answer:

angle b+54 = 90 degrees

90 - 54 = b

36° = angle b

5 0
3 years ago
Read 2 more answers
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