Use an area model to solve the expression 0.6 × 0.4. (6-4)

HELPPO What are the zeros of the function graphed below?

Leya [2.2K]

It's just wherever the function touches the x axis, so 5 and -1

7 0

3 years ago

PLS HELP (algebra 1) solve -19d + 8(7d - 14)

marishachu [46]

Answer:

$\huge\boxed{-19d + 8(7d - 14)=37d-112}$

Step-by-step explanation:

$-19d + 8(7d - 14)$

use the distributive property: a(b + c) = ab + ac

$-19d + (8)(7d)+(8)(- 14)=-19d+56d-112$

combine like terms

$=(-19d+56d)-112=37d-112$

4 0

3 years ago

1. ADEA has vertices D(8,4), E(2, 6), and F(3, 1). What are the vertices of the image after a dilation with a scale factor of 5

lubasha [3.4K]

Answer:

The vertices of the image are D' (40, 20), E' (10, 30), F' (15, 5)

Step-by-step explanation:

If the point (x, y) dilated by a scale factor k using the origin as a center of dilation, then its image is (kx, ky)

Let us use this rule to solve our question

∵ The vertices of ΔDEF are D (8, 4), E (2, 6), and F (3, 1)

∵ ΔDEF dilated by a scale factor 5

∴ k = 5

∵ The origin as the center of dilation

→ That means, multiply the coordinates of every point by 5

∴ D' = (8 × 5, 4 × 5)

∴ D' = (40, 20)

∴ E' = (2 × 5, 6 × 5)

∴ E' = (10, 30)

∴ F' = (3 × 5, 1 × 5)

∴ D' = (15, 5)

∴ The vertices of the image are D' (40, 20), E' (10, 30), F' (15, 5)

3 0

3 years ago

Before a computer is assembled, its motherboard goes through a special inspection. Assume only 85% of motherboards pass this ins

andreyandreev [35.5K]

Answer:

(a) The probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b) On average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

Step-by-step explanation:

Let X = number of motherboards that pass the inspection.

The probability that a motherboards pass the inspection is P (X) = p = 0.85.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is,

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that at least 13 of the next 15 motherboards pass inspection as follows:

P (X ≥ 13) = P (X= 13) + P (X = 14) + P (x = 15)

$={15\choose 13}0.85^{13}(1-0.85)^{15-13}+{15\choose 13}0.85^{14}(1-0.85)^{15-14}\\+{15\choose 13}0.85^{16}(1-0.85)^{15-15}\\=0.2856+0.2312+0.0874\\=0.6042$

Thus, the probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b)

Computed the expected number of motherboards should be inspected until a motherboard that passes inspection is found as follows:

$Expected\ value=\frac{1}{p}=\frac{1}{0.85}= 1.1764\approx1.18$

Thus, on average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

3 0

4 years ago

How much would it cost to build 10 houses if it costs 7 500 000 per house.

Andrej [43]

Answer:

75 000 000

Step-by-step explanation:

7 500 000 times 10 = 75 000 000

6 0

3 years ago

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