1×5 or 5×1 would be a factual of it
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
=========================
next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
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2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
5.476 rounded to the hundrdths is
5.48
Answer:
y ≈ 5.63
Step-by-step explanation:
m∠KLN and m∠NLM have to add up to m∠KLM
m∠KLN = 47°
m∠NLM = 16y°
m∠KLM = 137°
47 + 16y = 137
16y = 90
y = 45/8
y = 5.625
y ≈ 5.63
Answer:
576
Step-by-step explanation:
