Answer: 32%
Step-by-step explanation:
The total number of students that signed up for chemistry and algebra
two is 386.
Let x represent the number of students that signed up for both chemistry and algebra two
If 209 students signed up for algebra two, then the number of students that signed up for algebra two only is
209 - x
If 300 need to have signed up for chemistry, then the number of students that need to have signed up for chemistry only is 300 - x
Therefore,
x + 209 - x + 300 - x = 386
- x + 509 = 386
x = 509 - 386
x = 123
If 123 students would be signed up for both courses, then the probability that a student chosen at random from the 386 will be signed up for both of the courses is
123/386 × 100 = 32%
The minimum or maximum value of a quantity are what are used to maximize or minimize a function.
<em>The method for finding these minimum or maximum value is linear programming.</em>
<em />
Take for instance, the following parameters:
Subject to:
The above is an illustration of a linear programming.
It is useful in the following areas:
- To formulate real life problems
- To get an optimal solution
- To maximize profit and minimize cost
- Etc
Read more about linear programming at:
brainly.com/question/14225202
Here is the working:
17x5+5x11
=140
Therefore the answer is (D) 140 square units.
I hope this is helpful
Answer:
875 units
Step-by-step explanation:
35/5=7 AD and BC =7
25/5=5 the ratio of the to rect are 5
7(5)=35 EH and FG =35
25(35)=875
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Answer:
Kilogram of chicken = 1
Kilogram of tilapia = 3
Step-by-step explanation:
Cost of chicken = 150 per kilo
Cost of tilapia = 100 per kilo
Number of kilos of each if total cost should not exceed 450
Let :
Number of kilo of chicken = x
Number of tilapia kilo = y
The constraint :
150x + 100y ≤ 450
We could choose some reasonable values of x and y then, test the constraint ;
If x = 1 and y = 3
150(1) + 100(3) = 450
Hence,
1 kilo of chicken with 3 kilos of tilapia offers the greatest combination of Number of kilograms of tilapia and chicken that could be purchased and still satisfy the maximum cost constraint.
