Solution :
lt is given that in 18 mL of water their are
water molecules.
We know, that 1 molecule of water contains 2 atoms of hydrogen.
Hydrogen atom in 18 mL water is,
.
So, number of hydrogen atoms in 1 L = 1000 mL are :

Hence, this is the required solution.
Answer is: empirical formula is H₄N₂O₂.
m(unknown compound) = 8,5 g.
m(N₂) = 2,37 g.m(H₂O) = 3,04 g.
n(N₂) = m(N₂) ÷ M(N₂).
n(N₂) = 2,37 g ÷ 28 g/mol.
n(N₂) = 0,0846 mol.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 3,04 g ÷ 18 g/mol.
n(H₂O) = 0,168 mol.
n(H₂O) : n(N₂) = 0,168 mol : 0,0846 mol.
n(H₂O) : n(N₂) = 2 : 1.
Compound has four hydrogen, two oxygen and two oxygen.
Answer:
<u>7.44 grams CaCl2 will produce 10.0 grams KCl.</u>
Explanation:
The equation is balanced:
I've repeated it here, with the elements corrected for their initial capital letter.
CaCl2( aq) K2CO3( aq) → 2KCl( aq) CaCO3( aq)
This equation tells us that 1 mole of CaCl2 will produce 2 moles of KCl.
If we want 10.0g of KCl, we need to convert that mass into moles KCl by dividing by the molar mass of KCl, which is 74.55 grams/mole.
(10.0 grams KCl)/(74.55 grams/mole) = 0.1341 moles of KCl.
We know that we'll need half that amount of moles CaCl2, since the balanced equation says we'll get twice the moles KCl for every one mole CaCl2.
So we'll need (0.1341 moles KCl)*(1 mole CaCl2/2moles KCl) = 0.0671 moles CaCl2.
The molar mass of CaCl2 is 110.98 grams/mole.
(0.0671 moles CaCl2)*(110.98 grams/mole) = 7.44 grams CaCl2
<u>7.44 grams CaCl2 will produce 10.0 grams KCl.</u>
Answer:
Explanation:(1)base are slippery to touch e.g sodium hydroxide NaOH(aq)..
(2) They can be corrosive e.g pottasium hydroxide KOH(aq) and sodium hydroxide NOH(aq)
(3) They can act as electrolytes e.g NaOH(aq)
(4) they react to acids to form salt and water
Na0H(s)+HCL(aq)>>>NaCL(a)+H20(l)
(5)they dissolve in water to form hydroxyl ion
KoH(aq) >>>>>k+ + 0H-