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den301095 [7]
3 years ago
8

Name three sources of CO2

Chemistry
2 answers:
Firdavs [7]3 years ago
6 0
Deforestation and fires and respiration
dangina [55]3 years ago
4 0

Answer:

1.Respiration of animals and plants.

2.The burning of fossil fuels.

3.Bacteria decompose corpses.

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How do you make a animal cell?
GenaCL600 [577]

Answer:you cant make an animal cell

Explanation:

8 0
2 years ago
Read 2 more answers
Given the thermochemical equations below, What is the standard heat of formation of CuO(s)? 2 Cu2O(s) + O2(g) ---> 4 CuO(s) ∆
OlgaM077 [116]

-130KJ is the standard heat of formation of CuO.

Explanation:

The standard heat of formation or enthalpy change can be calculated by using the formula:

standard heat of formation of reaction = standard enthalpy of formation of product - sum of enthalpy of product formation

Data given:

Cu2O(s) ---> CuO(s) + Cu(s) ∆H° = 11.3 kJ

2 Cu2O(s) + O2(g) ---> 4 CuO(s) ∆H° = -287.9 kJ

CuO + Cu ⇒ Cu2O (-11.3 KJ)      ( Formation of Cu2O)

When 1 mole Cu20 undergoes combustion 1/2 moles of oxygen is consumed.

Cu20 + 1/2 02 ⇒ 2CuO (I/2 of 238.7 KJ) or 119.35 KJ

So standard heat of formation of  formation of Cu0 as:

Cu + 1/2 02 ⇒ CuO

putting the values in the equation

ΔHf = ΔH1 + ΔH2     (ΔH1 + ΔH2  enthalapy of reactants)

heat of formation = -11.3 + (-119.35)

                            = - 130.65kJ

-130.65 KJ is the heat of formation of CuO in the given reaction.

7 0
3 years ago
Read 2 more answers
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq)HCl(aq), as descr
ra1l [238]

Answer: 0.887 g of MnO_2 should be added to excess HCl(aq).

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 805 torr = 1.06 atm  (760torr=1atm)

V = Volume of gas = 235 ml = 0.235 L

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =25^0C=(25+273)K=298K

n=\frac{PV}{RT}

n=\frac{1.06atm\times 0.235L}{0.0820 L atm/K mol\times 298K}=0.0102moles

MnO_2(s)+4HCl(aq)\rightarrow MnCl_2(aq)+2H_2O(l)+Cl_2(g)

According to stoichiometry:

1 mole of chlorine is produced by = 1 mole of MnO_2

Thus 0.0102 moles of chlorine is produced by = \frac{1}{1}\times 0.0102=0.0102 moles of MnO_2

Mass of MnO_2 =moles\times {\text {Molar mass}}=0.0102mol\times 87g/mol=0.887g

0.887 g of MnO_2 should be added to excess HCl(aq).

7 0
3 years ago
Select the correct answer.
Burka [1]
C. Tetraphosphorus trisulfide
8 0
2 years ago
PLEASE ANSWER ASAP! 
uranmaximum [27]
Not for sure but i would say the its B rate please

6 0
2 years ago
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