Answer:
Sorry I’m not rlly sure but maybe the 2nd or the last
Explanation:
Answer:
Exergonic
Explanation:
The process is exergonic because it transfer energy from the system to the surrounds in the shape of light. It happens because of the Gibbs free energy (ΔG) which is lower than zero. If the reaction was Endergonic, the Gibbs free energy should be higher than zero. We can calculate it from the GIbbs-Helmholtz equation: ΔG = ΔH - T . ΔS. ΔH is enthalpy, T is the temperature and ΔS is entropy.
CF4 is the chemical equation of the compound
274 mL H3 O+ and fully neutralized
It will take one teaspoon of Mg(OH)2 to completely neutralize 2.00×10^2mL of H3O+.
<h3>What is the purpose of milk of magnesia?</h3>
- For a brief period of time, this medicine is used to relieve sporadic constipation.
- It is an osmotic laxative, which means that it works by drawing water into the intestines, which aids in causing bowel movement.
<h3>What dosage of milk of magnesia is recommended for constipation?</h3>
- Take Milk of Magnesia once day, preferably before bed, in divided doses, or as prescribed by a physician.
- suggested dosage: 30 mL to 60 mL for adults and kids 12 years of age and older. 15 mL to 30 mL for children aged 6 to 11 years.
learn more about milk of magnesia here
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the question you are looking for is
People often take milk of magnesia to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 teaspoon, which contains 4.00x 10^{2} mg of Mg(OH)_2. What volume of an HCl solution with a pH of 1.3 can be neutralized by one dose of milk of magnesia? If the stomach contains 2.00x10^{2}mL of pH 1.3 solution, is all the acid neutralized? If not, what fraction is neutralized?
The initial balanced equation of decomposition is:
2NaN3 —> 2Na + 3N2
Since 1 mole of a gas occupies 24dm^3 at room temperature and pressure:
72dm^3 / 24dm^3 = 3 moles of Nitrogen which required 2 moles of Sodium Azide.
Since moles = mass/Relative molecular mass or molar mass
2 moles x 65~ g/mol = 130g
For the empirical formula:
Element H N
% Mass 2.33% 97.7%
Mass/Mr 2.33 6.97
2.33 7~
Divide by lowest number
1 3
Therefore empirical formula is
H1N3
