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nirvana33 [79]
3 years ago
10

Given 5.86 grams of NaN3, how many grams of Na are produced?

Chemistry
1 answer:
Papessa [141]3 years ago
6 0

Answer:

what no entiendo nada jahag6

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Answer:

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3 years ago
An unknown metal sample has a mass : of 11.29. and a volume of 2 cm3. What is the : density of the unknown metal? ​
tatuchka [14]

Answer:

\boxed{\sf Density \ of \ the \ unknown \ metal = 5.645 \ g/cm^3}

Given:

Mass = 11.29 g

Volume = 2 cm³

To Find:

Density of unknown metal

Explanation:

Formula:

\boxed{ \bold{Density = \frac{Mass}{Volume}}}

Substituting value of mass & volume in the formula:

\sf \implies Density =  \frac{11.29}{2} \\  \\   \sf \implies Density =  5.645 \: g/cm^3

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3 years ago
What type of reaction is represented here:<br> 2K + Ca(OH)2 → 2KOH+ Ca
Anton [14]

Answer:

can you show me a picture of that element graph pls i dont really understand it

5 0
3 years ago
Which of the following would have the largest second ionization energy? Osr o Zr ΟΥ 0 Rb
Art [367]

Answer:

Rb

Explanation:

Second ionization energy is the energy required for the removal of the second loosely bonded valence electron from an isolated gaseous atom.

The given elements:

Rb , Sr, Y and Zr

These are the elements of the fifth period.

The electronic configuration of Rb - [Kr]5s^1

The electronic configuration of Sr - [Kr]5s^2

The electronic configuration of Y - [Kr]5s^24d^1

The electronic configuration of Zr - [Kr]5s^24d^2

<u>When one electron is removed from Rb, the cation attains the noble gas configuration due to which the removal of second electron from Rb is very very difficult. Thus, Rb has the largest second ionization energy.</u>

The values of the second ionization of these elements are:

Rb = 2633 kJ/mol

Sr = 1064.2 kJ/mol

Y = 1180 kJ/mol

Zr = 1270 kJ/mol

4 0
3 years ago
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Answer:

There will be no candy left because Laurie will give each friend 10 pieces of candy each

3 0
4 years ago
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