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dolphi86 [110]
3 years ago
14

Why is polymerization a type of addition reaction

Chemistry
1 answer:
KengaRu [80]3 years ago
5 0
Because it happens somewhere
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2C₂H6 + 702 —>4C02 + 6H₂O
navik [9.2K]

Answer:

975.56×10²³ molecules

Explanation:

Given data:

Number of molecules of C₂H₆ = 4.88×10²⁵

Number of molecules of CO₂ produced  =  ?

Solution:

Chemical equation:

2C₂H₆  + 7O₂     →      4CO₂ + 6H₂O

Number of moles of C₂H₆:

1 mole = 6.022×10²³ molecules

4.88×10²⁵  molecules×1mol/6.022×10²³ molecules

0.81×10² mol

81 mol

Now we will compare the moles of C₂H₆ with CO₂.

                     C₂H₆          :             CO₂

                          2           :               4

                           81         :           4/2×81 = 162 mol

Number of molecules of CO₂:

1 mole = 6.022×10²³ molecules

162 mol ×6.022×10²³ molecules / 1 mol

975.56×10²³ molecules

8 0
3 years ago
What can you predict about an element from its position in the periodic table?
Igoryamba
Yeah of-course!! It's valency by group most of the chemical property like electronegativity, ionization energy etc. by the combination of groups and periods...
8 0
3 years ago
The rare earth elements include A. the actinide series and the alkaline earth metals. B. the alkali metals and the transition me
kolezko [41]
The answer is A because Alkaline are gases in earth's atmosphere <span />
8 0
4 years ago
A mole of any atom or molecule has the same number of?
GarryVolchara [31]
The answer to this question is particles yes girl work slay that chem
6 0
3 years ago
Read 2 more answers
How much mass defect is required to release 5.5 x 1020 J of energy?
Montano1993 [528]

Answer : The mass defect required to release energy is 6111.111 kg

Explanation :

To calculate the mass defect for given energy released, we use Einstein's equation:

E=\Delta mc^2

E = Energy released = 5.5\times 10^{20}J

\Delta m = mass change = ?

c = speed of light = 3\times 10^8m/s

Now put all the given values in above equation, we get:

5.5\times 10^{20}Kgm^2/s^2=\Delta m\times (3\times 10^8m/s)^2

\Delta m=6111.111kg

Therefore, the mass defect required to release energy is 6111.111 kg

5 0
3 years ago
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