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morpeh [17]
3 years ago
6

What is the answer to this problem:

Mathematics
1 answer:
marishachu [46]3 years ago
7 0
115 complete bags with 13 left over.
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a jar contains 36 marbles. it has 20 red, 12 black, and 4 green marbles. two marbles are drawn; the first is not returned before
Igoryamba
P(red) first drawn:
20/36=5/9
P(red) second drawn:
19/35

95/315 or 19/63. As a result, the probability that both marbles are red is 19/63. Hope it help!
7 0
3 years ago
The polynomial 8x2 – 8x + 2 – 5 + x is simplified to 8x2 – gx – h. What are the value of g and h?
docker41 [41]

Answer:

Step-by-step explanation:

8x^2 - 8x + 2 - 5 + x.....combine like terms

8x^2 - 7x - 3 <=== g = 7 and h = 3

3 0
3 years ago
* PLEASE HELP CAN'T SOLVE *
emmainna [20.7K]

Answer:

Y=(4x)^3

Y=64x^3

Step-by-step explanation:

Y=(3√x)÷4

Making X subject of formula

4y= (3√x)

(4y)^3= (3√x)^3

(4y)^3 = X,

Replacing Y with X

Y=(4x)^3

Y=64X^3

4 0
3 years ago
What is the tens digit in the sum 7! + 8! + 9! + … + 2006!
Lena [83]

You can get the tens digit of any number <em>n</em> by computing the quotient

(<em>n</em> (mod 100)) / 10

and ignoring the remainder.

Taking the given sum (mod 100) gives

7! + 8! + … + 2006! ≡ 7! + 8! + 9! (mod 100)

since the last 1997 terms (i.e. 10! up to 2006!) in the sum are multiples of 100. That is,

• every term beyond 100! is obviously a multiple of 100

• every term beyond 25! contains a factor of both 4 and 25

• every term beyond 10! contains two factors each of both 2 and 5 (i.e. every factorial term contains 4, 5, and 10)

The remaining sum is easy to compute by hand:

7! + 8! + 9! = 7! (1 + 8 + 8 × 9) = 5040 × 81 = 408,240

so the tens digit is 4.

8 0
2 years ago
How to solve y=254-40x
pav-90 [236]

y=254-40x

Flip the equation

-40x+254=y

Add -254 to both sides

-40x+254+-254=y+-254

-40x=y-254

Divide both sides by -40

-40x/40=y-254/-40

x= -1/40 y + 127/20


I hope that's help !

8 0
3 years ago
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