It would be f(t)= 25^t+1
If you plugged in '2' as 't',
25^2+1= 15, 625 which uses the second day of the bacteria.
Answer:
Additive Identity I think, I'm not sure
Step-by-step explanation:
Tell me in the comments if I'm wrong.
Answer:
Q = -5/8 * 2/3
Multiply both numbers like your multiplying actual numbers.
<em><u>(-5 * 2)/(8*3)</u></em>
<h2><em><u>
</u></em></h2><h2><em><u>
A = -10/24 = -5/12</u></em></h2><h2><em><u>
Hope this helps</u></em></h2>
Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
Answer:
113
Step-by-step explanation:
