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Lana71 [14]
3 years ago
14

What is the mass in grams of one mole of any substance know as

Chemistry
1 answer:
likoan [24]3 years ago
3 0
Q. What is the mass in grams of one mole of any substance know as

A. Molar Mass
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Vitamin C, also known as ascorbic acid, is composed of 40.9 percent carbon, 4.6 percent hydrogen, and 54.5 percent oxygen. The m
Vladimir79 [104]

Answer:

Molecular formula is : C₆H₈O₆  

Explanation:

40.9 % of C, 4.6 % of H, 54.5 % of O means that in 100 g of ascorbic acid, we have 40.9 g of C, 4.6 g of H and 54.5 g of O.

If 1 mol of ascorbic acid weighs 176 g, let's determine the rules of three to know the grams of each element:

100 g of compound has ___ 40.9 g C __ 4.6 g H ___ 54.5 g O

176 g compound mus have:

(176 . 40.9) / 100 = 72 g of C

(176 . 4.6) / 100 = 8 g of H

(176 . 54.5) / 100 = 96 g of O

If we convert the mass to moles:

72 g . 1 mol / 12 g = 6 C

8 g . 1 mol/ 1g = 8 H

96 g . 1mol / 16 g = 6 O

Molecular formula is : C₆H₈O₆  

In conclussion, 1 mol of ascorbic acid has 6 moles of C, 8 moles of H and 6 moles of O

6 0
3 years ago
Your town is at sea level, and it is a comfortable room-
avanturin [10]

Answer:

68.6 m

Explanation:

Speed is defined as distance covered per unit time and expressed as

S=d/t

Where d is distance and t is speed.

Making d the subject of the above formula then

d=st

Substituting 343 m/s dor s and 0.200 s for s then

d=343*0.2=68.6 m

Therefore, the distance is 68.6 m

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3 years ago
What is the hydrogen ion concentration if the pH is 3.7?
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1.995 x 10^-4. To solve this, you had to do 10^-3.7.

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3 years ago
My theoretical yield of beryllium chloride was 10.7 grams. If my actual yield was 4.5 grams, what was my percent yield?
artcher [175]

Answer:

The percent yield of this reaction is 42.1 % (option B)

Explanation:

Step 1: Data given

Theoretical yield of beryllium chloride = 10.7 grams

actual yield of beryllium chloride = 4.5 grams

Step 2: Calculate the percent yield for this reaction

Percent yield = (actual yield / theoretical yield) * 100%

Percent yield = (4.5 grams / 10.7 grams ) * 100 %

Percent yield = 42.1 %

The percent yield of this reaction is 42.1 % (option B)

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3 years ago
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