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LenaWriter [7]
3 years ago
7

For the chemical reaction CaI2+2AgNO3-> 2AgI+Ca(NO3)2 how many moles of silver iodide will be produced from 205g of calcium i

odide
Chemistry
1 answer:
Colt1911 [192]3 years ago
6 0

Answer:

Moles of silver iodide produced = 1.4 mol

Explanation:

Given data:

Mass of calcium iodide = 205 g

Moles of silver iodide produced = ?

Solution:

Chemical equation:

CaI₂ + 2AgNO₃     →      2AgI + Ca(NO₃)₂

Number of moles calcium iodide:

Number of moles = mass/ molar mass

Number of moles = 205 g/ 293.887 g/mol

Number of moles = 0.7 mol

Now we will compare the moles of calcium iodide with silver iodide.

                     CaI₂         :           AgI

                         1           :             2

                       0.7         :           2×0.7 = 1.4

Thus 1.4 moles of silver iodide will be formed from 205 g of calcium iodide.

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What is the mass number of an ion with 107 electrons, 158 neutrons, and a 1 charge?
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3 years ago
Use the bond energy to calculate an approximate value of δh for the following reaction. Which is the more stable form of fno2?
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<h3>What is ∆H reaction?</h3>

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8 0
2 years ago
calculate atomic weight of silver which has two isotopes with the following properties : silver-107 (106.91 amu, 51.84% natural
Julli [10]

Answer: The atomic weight of silver is 107.87 amu

Explanation:

Mass of isotope silver-107  = 106.91 amu

% abundance of isotope silver -107 = 51.84% = \frac{51.84}{100}=0.5184

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Formula used for average atomic mass of an element :

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8 0
3 years ago
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