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LenaWriter [7]
3 years ago
7

For the chemical reaction CaI2+2AgNO3-> 2AgI+Ca(NO3)2 how many moles of silver iodide will be produced from 205g of calcium i

odide
Chemistry
1 answer:
Colt1911 [192]3 years ago
6 0

Answer:

Moles of silver iodide produced = 1.4 mol

Explanation:

Given data:

Mass of calcium iodide = 205 g

Moles of silver iodide produced = ?

Solution:

Chemical equation:

CaI₂ + 2AgNO₃     →      2AgI + Ca(NO₃)₂

Number of moles calcium iodide:

Number of moles = mass/ molar mass

Number of moles = 205 g/ 293.887 g/mol

Number of moles = 0.7 mol

Now we will compare the moles of calcium iodide with silver iodide.

                     CaI₂         :           AgI

                         1           :             2

                       0.7         :           2×0.7 = 1.4

Thus 1.4 moles of silver iodide will be formed from 205 g of calcium iodide.

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Explanation:

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2 years ago
If nitrogen and hydrogen combine in a combustion reaction, what would the product of the reaction be?
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Explanation:

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4 0
3 years ago
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Answer:

1. Ba2+ 2. Sr2+

Explanation:

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The chemical reactions are given below

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3 years ago
Explanation needed please!
VashaNatasha [74]

Answer:

Below

Explanation:

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     Subtract the number of protons (28) from the top number

4) there are 28 electrons in the neutral element of Nickel

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5) 62.9296694 atomic mass units

     Just search it up (unless your teacher wants you to calculate it)

6) there are 92 protons in this isotope

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7) there are 146 neutrons in this isotope

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8) there are 92 electrons in the neutral element of uranium

     Again just look at the periodic table and find U

9) 238.0507882 atomic mass units

10) 12C or carbon 12 is more likely to bond with oxygen that 14c carbon 14

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Hope this helps! Best of luck <3

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hram777 [196]
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