The missing data is the value of I.E and E.A for Cl and F, which are, Cl: I.E =1255 kJ/mol, E.A = -348.7 kJ/mol, F: I.E = 1678 kJ/mol, E.A = -327.8 kJ/mol.
Answer:
3.2
Explanation:
The electronegativity is the capacity of an atom to attract an electron in a bond. As higher is it, as higher the electron will be attracted. The ionization energy is the minimum energy necessary to remove one electron of the atom, transforming it on a cation. On the other hand, the electron affinity is the energy that is lost when the atom gains an electron and is transformed on an anion.
Calling the constant as K, and knowing that the electronegative of fluorine (F) is 4.0:
4 = K*(1678 - (-327.8))
2005.8K = 4
K = 2.00x10⁻³ mol/kJ
Thus, for chlorine (Cl):
Electronegativity = 2.00x10⁻³*(1255 - (-348.7))
Electronegativity = 3.2
If it produces heat then it would classify as a chemical change. Some other options are if it produces smell. Texure, matter of the material,and if it changes color are all also apart of classifying a chemical change.
We can use the combined gas law equation to find the new temperature

parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
P - pressure
P1 - 0.925 atm x 101 325 Pa/atm = 93 726 Pa
P2 - 625 torr x 133 Pa/torr = 83 125 Pa
V - volume
V1 - 10.1 L
V2 - 12.2 L
T - temperature in kelvin
T1 - 25 °C + 273 = 298 K
substituting these values in the equation

T = 319 K
temperature in celsius - 319 K - 273 = 46 °C