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3 years ago

An element that has been broken down and released particles and energy is said to be ____.

Chemistry

2 answers:

rjkz [21]3 years ago

8 0

It is said to be radioactive. Hope this was helpful because I'm learning this in school and I think it's right.

KatRina [158]3 years ago

5 0

Radioactive dating, is the answer
hope it helps (:

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In your opinion, why do you think the atomic models are not final?

julia-pushkina [17]

Answer:

because they change

Explanation:

It was based on theories and discoveries

7 0

2 years ago

My professor gave me two questions to solve using the Van Der Waals Equation. She told us to solve for P and the second one we h

Fed [463]

Answer:

P=atm

$b=\frac{L}{mol}$

Explanation:

The problem give you the Van Der Waals equation:

$(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT$

First we are going to solve for P:

$(P+\frac{n^{2}a}{V^{2}})=\frac{nRT}{(V-nb)}$

$P=\frac{nRT}{(V-nb)}-\frac{n^{2}a}{v^{2}}$

Then you should know all the units of each term of the equation, that is:

$P=atm$

$n=mol$

$R=\frac{L.atm}{mol.K}$

$a=atm\frac{L^{2}}{mol^{2}}$

$b=\frac{L}{mol}$

$T=K$

$V=L$

where atm=atmosphere, L=litters, K=kelvin

Now, you should replace the units in the equation for each value:

$P=\frac{(mol)(\frac{L.atm}{mol.K})(K)}{L-(mol)(\frac{L}{mol})}-\frac{(mol^{2})(\frac{atm.L^{2}}{mol^{2}})}{L^{2}}$

Then you should multiply and eliminate the same units which they are dividing each other (Please see the photo below), so you have:

$P=\frac{L.atm}{L-L}-atm$

Then operate the fraction subtraction:

P= $P=\frac{L.atm-L.atm}{L}$

$P=\frac{L.atm}{L}$

And finally you can find the answer:

P=atm

Now solving for b:

$(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT$

$(V-nb)=\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}$

$nb=V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}$

$b=\frac{V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}}{n}$

Replacing units:

$b=\frac{L-\frac{(mol).(\frac{L.atm}{mol.K}).K}{(atm+\frac{mol^{2}.\frac{atm.L^{2}}{mol^{2}}}{L^{2}})}}{mol}$

Multiplying and dividing units,(please see the second photo below), we have:

$b=\frac{L-\frac{L.atm}{atm}}{mol}$

$b=\frac{L-L}{mol}$

$b=\frac{L}{mol}$

7 0

3 years ago

2. What is the mass of 16.3 L of helium gas?

lilavasa [31]

(16.3 L) / (22.414 L/mol) x (4.0026 g He/mol) = 2.91 g

3 0

3 years ago

Read 2 more answers

Using the Law of Conservation of Matter, determine the number of grams of iron sulfide (FeS) that will be produced in this react

vazorg [7]

The Law of Conservation of Mass states that the mass of reactants entering a reaction must be equal to the mass of the products exiting it. In this case, we only have 2 reactants, Fe and S, and we only have 1 product, FeS. Therefore we expect the total mass of the Fe and S reactants to equal the mass of FeS. This gives us 112 g + 64 g = 176 g of FeS, which is choice D.

4 0

3 years ago

Read 2 more answers

A gas has a pressure of 0.470 atm at 60.0 C. What is the pressure at standard temperature?

OLEGan [10]

Answer:

P2=0.385atm

Explanation:

step one:

Given that the temperature T1= 60 Celcius

we can convert this to kelvin by adding 273k to 60 Celcius

we have T1= 333k

pressure P1= 0.470 atm

step two:

we know that the standard temperature is T2= 273K

Applying the temperature and pressure relationship we have

P1/T1=P2/T2

substituting our given data we have

0.47/333=P2/273

cross multiply we have

P2= (0.47*273)/333

P2= 128.31/333

P2=0.385 atm

6 0

3 years ago