Question

You need 4.0 ounces of a steroid ointment. if there are 16 oz in 1 lb, how many grams of ointment does the pharmacist need to prepare

Answer 1

The given units are the units of masses which are interconvertable.

It is given that:

$1 lb = 16 oz$

Now, converting $kg to lb$:

Since, $1 kg = 2.20462 lb$

So, $\frac{0.0625 lb}{1 oz}\times \frac{1 kg}{2.20462 lb}$

Now converting $kg to g$:

Since, 1 kg = 1000 g

So, $\frac{0.0625 lb}{1 oz}\times \frac{1 kg}{2.20462 lb}\times \frac{1000 g}{1 kg} = 28.349 \frac{g}{oz}$

For $4 oz$:

$28.349\frac{g}{oz} \times 4 oz = 113.396 g$

Thus, $113.396 g$ of ointment needed to be prepared by the pharmacist.