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3 years ago

How to solve 18 + 3(9f-13)

Mathematics

2 answers:

Semmy [17]3 years ago

8 0

Step-by-step explanation:

<em>Step 1: Distrbute 3 into (9f - 13)</em>

3 • 9f = 27f

3 • 13 = 39

18 + 27f - 39

<em>Step 2: Solve like-terms</em>

(18 and 39 are the only like terms. 27f and 39 aren't like terms since 39 doesn't have a variable therefore, you can't solve 27f - 39)

39 - 18 = 21

ANSWER:

27f - 21

Hope this is correct!

<h3><em>- justy⊕∪rultimαtefαngirl</em></h3>

Marrrta [24]3 years ago

6 0

Answer:

Distribute so it would be 18+27f-39

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Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

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a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

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2 years ago

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ASHA 777 [7]

Answer:

$x=10$

Step-by-step explanation:

Notice that all three sides of the given triangle has one tick mark.

This means that all three sides are congruent, meaning that we have an equilateral triangle.

And for equilateral triangles, all three angles are also congruent.

So:

$\angle CBA=\angle BAC=\angle ACB$

Also, recall that the interior angles of a triangle is always 180. Thus:

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3 years ago