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3 years ago

How to solve 18 + 3(9f-13)

Mathematics

2 answers:

Semmy [17]3 years ago

8 0

Step-by-step explanation:

<em>Step 1: Distrbute 3 into (9f - 13)</em>

3 • 9f = 27f

3 • 13 = 39

18 + 27f - 39

<em>Step 2: Solve like-terms</em>

(18 and 39 are the only like terms. 27f and 39 aren't like terms since 39 doesn't have a variable therefore, you can't solve 27f - 39)

39 - 18 = 21

ANSWER:

27f - 21

Hope this is correct!

<h3><em>- justy⊕∪rultimαtefαngirl</em></h3>

Marrrta [24]3 years ago

6 0

Answer:

Distribute so it would be 18+27f-39

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3 years ago

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3:5

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3 years ago

What % of $30,000 = $15,000

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3 years ago

Give the equation of a line that goes through the point ( − 21 , 2 ) and is perpendicular to the line 7 x − 4 y = − 12 . Give yo

nlexa [21]

Given:

Equation of line $7x-4y=-12$ .

To find:

The equation of line that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.

Solution:

The given equation of line can be written as

$7x-4y+12=0$

Slope of line is

$\text{Slope}=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}$

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$m_1=\dfrac{7}{4}$

Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is

$m_1m_2=-1$

$m_2=-\dfrac{1}{m_1}$

$m_2=-\dfrac{4}{7}$ $[\because m_1=\dfrac{7}{4}]$

Now, the slope of perpendicular line is $m_2=\dfrac{4}{7}$ and it goes through (-21,2). So, the equation of line is

$y-y_1=m_2(x-x_1)$

$y-2=-\dfrac{4}{7}(x-(-21))$

$y-2=-\dfrac{4}{7}x-\dfrac{4}{7}(21)$

$y-2=-\dfrac{4}{7}x-12$

$y=-\dfrac{4}{7}x-12+2$

$y=-\dfrac{4}{7}x-10$

Therefore, the required equation in slope intercept form is $y=-\dfrac{4}{7}x-10$ .

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3 years ago