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3 years ago

9

Janice has a pack of 36 cookies. She splits the cookies equally among herself and eight of her friends. With the cookies she has

left, she eats one and puts the rest in a bag for later. How many cookies does she put in the bag?

2 answers:

vivado [14]3 years ago

5 0

3 right because there are 8 friends counting her, which is 9 so 36 cookies divided by 9 is 4 so they each get 4. janice doesn't eat all her cookies and she eats one and puts the other 3 in her bag...?

LekaFEV [45]3 years ago

5 0

The answer is 3! :)

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Add. Simplify the answer to lowest terms before entering the numerator and denominator in their boxes. 11/16 + 3/16

myrzilka [38]

Answer:

The answer is 7/8.

Step-by-step explanation:

If you add 11/16 to 3/16, you'll get 14/16. 14/16 has two numbers that are divisible by 2, so when you divide 14/16 by 2 you'll get 7/8 which is 14/16 in a simplified form. 7 is prime and you can't divide it down any more, but 8 i'snt the same way. The rule is, whatever you do to one side, you have to do to the other. You can divide 8, but not 7; therefore, you cannot simplify the fraction any further.

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andrew-mc [135]

Data:
r (radius) = 14 m
h (height) = 6 m
v (volume) = ?

Formula:
$V = \pi *r^2*h$

Solving:
$V = \pi *r^2*h$
$V = \pi *14^2*6$
$V = \pi *196*6$
$\boxed{\boxed{V = 1176 \pi\:m^3}}\end{array}}\qquad\quad\checkmark$

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3 years ago

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

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3 years ago

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Svetllana [295]

The cost for six pencils would be a total of 150p
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Can someone help me out with this

katen-ka-za [31]

Answer:

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Step-by-step explanation:

Use the cosine ratio, $cosine=\frac{adjacent}{hypotenuse}$ . Insert the values:

$cos25=\frac{4}{x}$

Isolate x. Multiply both sides by x:

$x*(cos25)=x*(\frac{4}{x})\\\\x*cos25=4$

Divide both sides by cos 25:

$\frac{x*cos25}{cos25}=\frac{4}{cos25}\\\\x=\frac{4}{cos25}$

Insert into a calculator:

$x=4.414$

Round to the nearest hundredth:

$x=4.41$

Done.

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3 years ago