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3 years ago

7

Determine the value of x for which a || b if m<30=80-x and m<7=90-2x.

1 answer:

abruzzese [7]3 years ago

8 0

D. 10

m<3 = 80 - (10) = 70
m<7 = 90 - (20) = 70

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3 years ago

Please help and thank you

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Answer:

$b_{1}=\frac{2A}{h}-b_{2}$

Step-by-step explanation:

Given: $A=\frac{1}{2}(b_{1} +b_{2})h$

We need to completely isolate $b_{1}$ to solve.

$A=\frac{1}{2}(b_{1} +b_{2})h$

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Answer:

The mean perimeter of frame = 38 cm

Step-by-step explanation:

By perimeter of a rectangle, the formula is given as:

Perimeter of rectangle = 2(A + B)

Going by the illustration in the question, the perimeter is

==> 2(32 + 44) = 152 cm.

However, we a given the mean perimeter of the frame which are:

32 and 44. We can either choose to say; each sides is (32 by 32) and (44 by 44). Or we consider it in mean/average term as given: (32 by 44).

Case 1: To obtain the mean perimeter of the frame using the first scenario, we say:

Mean perimeter = (32+32+44+44)/4 = 38 cm.

Case 2: We can simply say:

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Graphically: Assuming that the frame is given below

32 cm

---------------------------------

| |

| |

44 cm| | 44 cm

| |

| |

| |

----------------------------------

32 cm

The mean of upper frame/bars = 32 cm

The mean of side frame/bars = 44 cm

Hence, the mean of the perimeter = (32 + 44)/2 = 38 cm

OR,

we take the sum of all the sides (32 + 44 + 32 + 44) and divide by total number of sides (4). That is;

The mean of the perimeter = (32 + 44 + 32 + 44)/4 = 38 cm

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