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Tju [1.3M]
3 years ago
11

"in an ionic compound, the size of the ions affects the internuclear distance (the distance between the centers of adjacent ions

), which affects lattice energy (a measure of the force needed to pull ions apart); the lattice energy, in turn, affects the enthalpy of solution. Based on ion sizes, arrange these compounds by their expected heats of solution." csbr, csi, csf, cscl
Chemistry
2 answers:
Angelina_Jolie [31]3 years ago
8 0

<em>As we all know the different atoms and paste in different crystal forms.</em>

<u>Explanation:</u>

And when the atoms are brought from <em>infinity to that position position</em> shall be released the energy that can be released on this occasion of bringing the iron from Infinity 2 in that reformist would give lattice energy now you also know that right only for different <em>crystal formations</em> are different.

Hence have <em>different sizes of Ions</em> to now arranging these compounds in terms of energy they have Starting from most endothermic to the most <em>exothermic compounds</em> are <em>CsF < CsCl < CsBr < CsI also it can be added even for greater values.</em>

kherson [118]3 years ago
7 0

Explanation:

As lattice energy is the amount of force or energy required to pull the ions apart. Therefore, smaller is the size of combining atoms more will the presence of force of attraction in its ions.

Hence, high energy will be needed to break the bond and therefore, an increase in lattice energy will occur.

Since, in the given options the cation is same and only the anion is different. And, electron charge density of fluoride is the highest whereas iodine has the least electron charge density.

Hence, CsF will have the highest lattice enthalpy. Hence, trend of lattice energy for the given compounds will be as follows.

                    CsF > CsCl > CsBr > CsI

As CsF requires high energy to split into ions so, it will be endothermic in nature.

Thus, we can conclude that the given compounds are arranged by their expected heats of solution (most endothermic to most exothermic) in increasing order as follows.

                  CsF < CsCl < CsBr < CsI

                       

 

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Which of the following pure compounds will exhibit hydrogen bonding?
zimovet [89]

Explanation:

For a compound to show hydrogen bonding it is necessary that the hydrogen atom of the compound should be attached to more electronegative atom like fluorine, oxygen or nitrogen.

For example, CH_{3}CH_{2}OH, CH_{3}NH_{2} and NH_{3} all these compounds contain an electronegative atom attached to hydrogen atom.

Therefore, these pure compounds will exhibit hydrogen bonding.

Thus, we can conclude that out of the given options CH_{3}CH_{2}OH, CH_{3}NH_{2} and NH_{3} are the pure compounds which will exhibit hydrogen bonding.

4 0
3 years ago
if the reduced row echelon form of the augmented matrix for a linear system has a row of zeros, then the system must have infini
BigorU [14]

Answer:

False

Explanation:

If the row echelon form of the augmented matrix for a linear system has a row of zeros, then the there must not have infinitely many solution,

we can prove this with an example. Suppose we have an augmented matrix A for linear system with a row of zeros,

             1     0      0      1

A=         0     1       0    -2

            0     0       1    - 1

            0    0       0     0

we get

x1=1

x2=-2

x3=-1

so, system has an unique solution.

we can take inference that the given statement is wrong

7 0
3 years ago
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


4 0
3 years ago
The acid HOCl (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles
sergejj [24]

<u>Answer:</u> The expression for equilibrium constant is K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

For the general chemical equation:

aA+bB\rightleftharpoons cC+dD

The expression for K_c is given as:

K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical reaction:

2HgO(s)+H_2O(l)+2Cl_2(g)\rightleftharpoons 2HOCl(aq.)+HgO.HgCl_2(s)

The expression for K_{eq} is given as:

K_{eq}=\frac{[HOCl]^2[HgO.HgCl_2]}{[HgO]^2[H_2O][Cl_2]^2}

The concentration of solid is taken to be 0.

So, the expression for K_{eq} is given as:

K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}

3 0
3 years ago
How many moles of water are produced if 5.43 mol PbO2 are consumed
Mariana [72]
It has to be understood that 2 moles of oxygen are there in each mole of PbO2. Then it has to be calculated for 2 moles of oxygen.

Amount of oxygen = 2 * 5.43 moles
                              = 10.86 moles
Now it is also a fact that each mole of H2O contains 1 mole of oxygen. Then it can be easily concluded that 10.86 moles of water will be produced. I hope the procedure is clear enough for you to understand.
5 0
3 years ago
Read 2 more answers
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