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Valentin [98]
3 years ago
6

Use the given Nernst equation and reaction to solve this problem. What is the potential of this cell with the given conditions?

Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
7 0

Answer:

The 2nd one is the one

Explanation:

and it isn't writen out all the way

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Electrochemical processes are written with the oxidation half-reaction on the left and the reduction reaction on the right; wher
CaHeK987 [17]

Answer:

B) FALSE.

Explanation:

First off, its important to understand the following concepts;

A half reaction is either the oxidation or reduction reaction component of a redox (Oxidation - Reduction) reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction.

Often, the concept of half-reactions is used to describe what occurs in an electrochemical cell, such as a Galvanic cell battery. Half-reactions can be written to describe both the metal undergoing oxidation (known as the anode) and the metal undergoing reduction (known as the cathode).

Half equations simply much just breaks the reaction into oxidation and reduction steps (irrespective of the order, whether left or right).

An example of half equation is given below;

Mg → Mg2+ + 2e− (Oxidation)

Cu2+ + 2e− → Cu (Reduction)

The answer is false because; oxidation-reduction reactions are NOT represented by equations that group the reaction participants into reactants and products. Rather they are

8 0
3 years ago
If 0.300 moles of Cl2 is mixed with 0.600 moles of F2 in a 5.00 L rigid reaction vessel, what is the final pressure in the vesse
sesenic [268]

Answer:

29.0

Explanation:

3 0
3 years ago
2. To what volume will you have to dilute 20.0 ml of a 8 M HCl solution to make a 0.35 M
GrogVix [38]

Answer:

You need to dilute 8 M HCl to 0.35 M to make 457 mL.

Explanation:

Use the equation M₁V₁=M₂V₂

Convert the mL to L : 20 mL= 0.02 L

8 M x 0.02 L = 0.35 M x V₂

V₂ = 0.4571429 L = 457 mL

3 0
3 years ago
Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr
VikaD [51]

Answer : The value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

Explanation :

The balanced cell reaction will be,

Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)

The half-cell reactions are:

Oxidation reaction (anode) : Pb(s)\rightarrow Pb^{2+}(aq)+2e^-

Reduction reaction (cathode) : 2Ag^+(aq)+2e^-\rightarrow 2Ag(g)

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}

where,

\Delta G^o = standard Gibbs free energy

F = Faraday constant = 96500 C

n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential of the cell = 0.93 V

Now put all the given values in the above formula, we get:

\Delta G^o=-2\times 96500\times 0.93

\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol

Now we have to calculate the value of 'K'.

\Delta G^o=-RT\ln K

where,

\Delta G_^o =  standard Gibbs free energy  = -180 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K

K=3.6\times 10^{31}

Therefore, the value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

5 0
3 years ago
Which type of molecule is shown below?
zubka84 [21]

Answer:

\boxed{\mathrm{Alkene}}

Explanation:

The hydrocarbon shown has a double bond. Hydrocarbons with double bonds are known as alkenes.

Cyclic alkanes have cyclic structure.

Alkanes only have single bonds.

Alkynes have triple bonds.

8 0
3 years ago
Read 2 more answers
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